= (y+6) +y =10
= 2y + 6 = 10
= 2y = 4
Y= 2
Answer:
5
Step-by-step explanation:
Put -6 where x is and do the arithmetic.

<h3>
Answer: 8p^3 + 10p^2 + 14p</h3>
Explanation:
The outer term 2p is distributed among the three terms inside the parenthesis. We will multiply 2p by each term inside
2p times 4p^2 = 2*4*p*p^2 = 8p^3
2p times 5p = 2*5*p*p = 10p^2
2p times 7 = 2*7p = 14p
The results 8p^3, 10p^2 and 14p are added up to get the final answer shown above. We do not have any like terms to combine, so we leave it as is.
Answer:
-0.4 = −2/5
Step-by-step explanation:
Rewrite the decimal number as a fraction.
-0.4/1
Multiply to remove 1 decimal places.
-0.4/1 x 10/10 =4/10
Find the GCF.
4 ÷ 2/10 ÷ 2 = 2/5
x = 2/5
-2/5
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab,
is equal to
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus,
. Since a and b were generic elements of H, then H/G is abelian.