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Eduardwww [97]
3 years ago
7

A gemstone is cut in the shape of a triangular pyramid. The area of the base of the pyramid is 42 square millimeters. The height

of the pyramid is 4 millimeters. What is the volume of the gemstone? (Recall the formula V = one-third B h.)
Mathematics
1 answer:
never [62]3 years ago
7 0

Answer:

the volume of the gemstone is 56 millimeters^3

Step-by-step explanation:

The computation of the volume of the gemstone is shown below:

As we know that

The volume of the triangular pyramid is

= (1 ÷ 3) × (base area) × h

Now put the given values to the above formula

= 1 ÷ 3 × 42 × 4

=  56 millimeters^3

Hence, the volume of the gemstone is 56 millimeters^3

The above formula should be used and the same should be considered

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Subtract. Write the answer as a fraction simplified to lowest terms
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Answer:

3/14

Step-by-step explanation:

4/7 - 5/14

Get a common denominator of 14

4/7 *2/2 - 5/14

8/14 - 5/14

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A basketball team scored 78 points in their championship win over their rival. The team scored 25 baskets worth 2 points and mad
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3 years ago
Una heladeria dispone de 20 frutas distintas para elaborar sus malteadas. Si los clientes pueden elegir tres sabores para mezcla
Dahasolnce [82]

Answer:

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

Step-by-step explanation:

En este caso, el cliente que adquiere una malteada de tres sabores distintos sigue el siguiente procedimiento:

1) El primer sabor sale de cualquiera de las 20 frutas disponibles.

2) El segundo sabor es distinto al primer sabor, es decir, que sale de las 19 frutas restantes.

3) El tercer sabor es distinto al primer sabor y al segundo sabor, es decir, que sale de las 18 frutas restantes.

Puesto que existe una doble conjunción y que puede importar el orden según la preferencia del cliente, se habla matemáticamente de una permutación, definida como:

n\mathbb{P}k = \frac{n!}{(n-k)!} (1)

Donde:

n - Número de sabores disponibles, adimensional.

k - Número de sabores escogidos, adimensional.

Si tenemos que n = 20 y k = 3, entonces la cantidad de malteadas de tres sabores distintos es:

n\mathbb{P}k = \frac{20!}{(20-3)!}

n\mathbb{P}k = \frac{20!}{17!}

n\mathbb{P}k = 20\cdot 19\cdot 18

n\mathbb{P}k = 6840

Existen 6840 permitaciones de malteadas de tres sabores distintos que la heladería puede ofrecer.

5 0
3 years ago
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