Question

Ten is no more than four times the sum of twice a number and three.

Answer 1

$x-searched\ number\\\\10 \leq 4(2x+3)\\10 \leq 8x+12\ \ \ \ \ \ \ |subtract\ 12\\10-12 \leq 8x\\-2 \leq 8x\ \ \ \ \ \ \ \ \ |:8\\x \geq -\frac{2}{8}\\x \geq -\frac{1}{4}\\\\x\in[\frac{1}{4},+\infty)$

Answer 2

Set up an equation when n is the number and solve:
 10 </= 4(2n + 3)
 10 </= 8n + 12
-12             - 12
-2 = 8n
/8   /8
n = >/= -1/4
The number is less than or equal to -1/4. 
Hope this helps!