2 years ago

The product of two consecutive integers is 56.find the the integers.

Mathematics

1 answer:

defon2 years ago

4 0

Let, the integers = x,(x+1)

x*(x+1) = 56

x²+x = 56

x²+x-56 = 0

x²+8x-7x-56=0

x(x+8)-7(x+8)=0

x+8= 0 OR x-7=0

x = -8 OR x = 7

it would be -8 & -7 or 7 & 8

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<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-%2014x%20%2B%2024" id="TexFormula1" title="2x^{2} - 14x + 24" alt="2x^{2} - 14

s344n2d4d5 [400]

Answer:

Factorized

$=(2x-8)(x-3)$

Roots : 4 , 3

Step-by-step explanation:

If it is to factorize :

$2x^2 - 14x + 24 = 2x^2 -6x-8x +24$

$=2x(x-3)-8(x-3)\\=(2x-8)(x-3)$

If it is to solve for x :

$2x^2 -1 4x + 24 = 0\\(2x-8)(x-3)=0\\2x - 8 = 0 \ , \ x - 3 = 0\\2x = 8 \ , \ x = 3\\x = 4 , 3$

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2 years ago

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NikAS [45]

Answer:

when there are no parentheses around the base, this being -2 we put parentheses around the the 2 and the exponent so it will look like -(2^6) making whatever answer you get negative.

when you put parentheses around the base (-2)^6 you will get 64

Step-by-step explanation:

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<u>Explanation:</u>

Average rate of change is slope: $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ . Need to find the y-coordinates:

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