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3 years ago

Tina plans to make wooden frames to put her two triangular art pieces in.

Mathematics

2 answers:

telo118 [61]3 years ago

7 0

Answer: 54 in.

Step-by-step explanation: So, the problem does something a little sneaky, and that is they ask for the TOTAL amount of wood needed for triangle DFG. And to find that, we simply have to multiply side AC by 3 to get side DG. We do this because triangle ABC is 3 times as small as triangle DFG. Then, add your side DG that you just got, (21) to side FG and FD to get the total amount of wood needed, 54 in.

Lena [83]3 years ago

6 0

Answer:

54 in

Step-by-step explanation:

I took test

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The vector equation of the line is $\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)$ and parametric equations for the line are $x=4t$ , $y=11-4t$ , $z=-8+6t$ .

Step-by-step explanation:

It is given that the line passes through the point (0,11,-8) and parallel to the line

$x=-1+4t$

$y=6-4t$

$z=3+6t$

The parametric equation are defined as

$x=x_1+at,y=y_1+bt,z=z_1+ct$

Where, (x₁,y₁,z₁) is point from which line passes through and <a,b,c> is cosine of parallel vector.

From the given parametric equation it is clear that the line passes through the point (-1,6,3) and parallel vector is <4,-4,6>.

The required line is passes through the point (0,11,-8) and parallel vector is <4,-4,6>. So, the parametric equations for the line are

$x=4t$

$y=11-4t$

$z=-8+6t$

Vector equation of a line is

$\overrightarrow {r}=\overrightarrow {r_0}+t\overrightarrow {v}$

where, $\overrightarrow {r_0}$ is a position vector and $\overrightarrow {v}$ is cosine of parallel vector.

$\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)$

Therefore the vector equation of the line is $\overrightarrow {r}=(11j-8k)+t(4i-4j+6k)$ and parametric equations for the line are $x=4t$ , $y=11-4t$ , $z=-8+6t$ .

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