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Olenka [21]
3 years ago
11

Sierra walks her dog Pepper twice a day. Her evening walk is two and a half times as far as her morning walk. At the end of the

week, she tells her mom, “I walked Pepper for 30 miles this week!”
How long is her morning walk?



Group of answer choices

3.2 miles

12 miles

1.2 miles

5.5 miles
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
4 0
W=30/24.5≈1.2.

Therefore, Sierra's morning walk is about 1.2 miles.
kkurt [141]3 years ago
3 0
It is approximately 1.2 miles
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Your engineering firm is asked to specify the maximum load for the elevators in a new building: Each elevator has mass 490 kg wh
steposvetlana [31]

Answer:

a) m =589.734kg

b) n = 8 people (rounded down)

Step-by-step explanation:

The first step is to calculate the maximum load after safety considerations (T_{max}

Since we know that the maximum tension the cables can withstand is 19500N (or 19.5kN). To calculate (T_{max} we multiply this value by \frac{2}{3} (as per the given safety consideration.

Hence

T_{max} = \frac{2}{3} (19500) \\ T_{max} = 13000N

a) Now to find the maximum load in kgs, we use the following formula

(m_{0} + m)(g + a) = T_{max}

Where

m_{0} = mass of elevator

m = maximum load

g = acceleration due to gravity

a = maximum acceleration of elevator

Inputting the values and solving

m_{0} + m)(g + a) = T_{max}\\ (490 + m)(9.8 + 2.24) = 13000\\ 12.04m = 7100.4\\ m = 589.734kg

Hence the maximum load is m =589.734kg

b) To find the number of people (n) we divide the value of m by 70kg

n = 589.734 / 70

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In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0 respectively. If the coefficient sk
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Answer:

a) The third quartile Q₃ = 56.45

b) Variance \mathbf{ \sigma^2 =2633.31}

Step-by-step explanation:

Given that :

Q_1  =  30.8

Median Q_2 =  48.5

Mean  = 42

a) The mean is less than median; thus the expression showing the coefficient of skewness is given by the formula :

SK = \dfrac{Q_3+Q_1-2Q_2}{Q_3-Q_1}

-0.38 = \dfrac{Q_3+30.8-2(48.5)}{Q_3-30.8}

-0.38Q_3  + 11.704  =  Q_3  +30.8  - 97

1.38Q_3  =  77.904

Divide both sides by 1.38

Q_3 = 56.45

b) The objective here is to determine the approximate value of the variance;

Using the relation

SK_p = \dfrac{Mean- (3*Median-2 *Mean) }{\sigma}

-0.38= \dfrac{42- (3 *48.5-2*42) }{\sigma}

-0.38= \dfrac{(-19.5) }{\sigma}

-0.38* \sigma = {(-19.5) }{}

\sigma =\dfrac {(-19.5) }{-0.38 }

\sigma =51.32

Variance =  \sigma^2 =51.32^2

\mathbf{ \sigma^2 =2633.31}

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3 years ago
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