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Genrish500 [490]
3 years ago
5

A school ordered 3 large boxes if board markers. After giving 15 markers to each of 3 teachers, there were 90 markers left. How

many markers were originally in each box
Mathematics
1 answer:
Elis [28]3 years ago
8 0

Answer:

45 markers were in each box.

Step-by-step explanation:

To solve the problem, the total number of markers must be calculated and then divided by the number of original large boxes.

The number of markers is calculated as follows:

90 left over, 15 for each teacher and there are three teachers, that is, 15 * 3 = 45

That is: 90 + 45 = 135 markers in total.

Therefore per box would be 135/3 = 45 markers were in each box.

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Order the following numbers from greatest to least: 2, -1 , 2.58, -1.65. -1, -1.65, 2, 2.58 2.58, 2, -1.65, -1 2.58, 2, -1 , -1.
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The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars ea
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A) zeroes

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Extract common factor:

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Factor (find two numbers that sum -10 and its product is 21)

P(n) = -250(n - 3)(n - 7)

Zeroes ==> n - 3 = 0  or n -7 = 0
Then n = 3 and n = 7 are the zeros.

They rerpesent that if the promoter sells tickets at 3  or 7 dollars the profit is zero.

B) Maximum profit

Completion of squares

n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4

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C) Axis of symmetry

Vertex = (h,k) when the equation is in the form A(n-h)^2 + k

Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000

Vertex = (5, 1000) and the symmetry axis is n = 5.



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3 years ago
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