Step-by-step explanation:
Let's get our relevant base equations listed out:
d = 2r
area = pi*r²
c = πd
Thus, d=2*5m = 10m, c=π*10m=10π m, and area = 25m²*π
Feel free to ask further questions!
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)
(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)
(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)
(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.
The final solution is y=-5/3x-10
I hope this answer helps, it’s kinda messy, but it’s still understandable (I guess)
Answer:
t≥-25
Step-by-step explanation:
this is becuaset ≥ -25 shows that it can not fall under -25, but can be equal to -25.
