Answer:
2.1 , 2.103 , 2.13 , 2.1312
Step-by-step explanation:
Look at the first place, and see if it's the same, if it is, then you move to the next place. If the place is empty, fill it with a 0 and go from there.
Answer:
x=2 and y=−6
sorry this is pretty long, I did not know if you needed the steps or not
Step-by-step explanation:
−2y−10=x;−10x−y=−14
Solve−2y−10=x for x
−2y−10=x
−2y−10+−x=x+−x
−x−2y−10=0
−x−2y−10+2y=0+2y
−x−10=2y
−x−10+10=2y+10
−x=2y+10
-x/-1=2y+10/-1
x=−2y−10
Substitute−2y−10 for x in−10x−y=−14
−10x−y=−14
−10(−2y−10)−y=−14
19y+100=−14
19y+100+−100=−14+−100
19y=−114
19y/19=-114/19
y=-6
Substitute−6 for y in x=−2y−10
x=−2y−10
x=(−2)(−6)−10
x= 2
x=2 and y=−6
Answer:
answer C (0,-9)
Step-by-step explanation:
the line passes through (0,-9)
Answer:
Length of rectangle = 16 cm
Width of rectangle = 4 cm
Step-by-step explanation:
Given:
Area of rectangle = 64 cm²
Find:
Length and width
Computation:
Assume;
Length of rectangle = a
So,
Width of rectangle = a -12
Area of rectangle = l x b
So,
a(a-12) = 64
a² - 12a - 64 = 0
a² - (16-4)a - 64 = 0
a² - 16a+ 4a - 64 = 0
a (a-16) + 4(a-16)= 0
(a-16)(a+4) = 0
a= 16 , a = -4
So,
Length of rectangle = 16 cm
Width of rectangle = a -12
Width of rectangle = 16 -12
Width of rectangle = 4 cm
I’m pretty sure it has potential energy. Because a charge battery can be charged. So it can have energy