Step-by-step explanation:
You have to do first and second derivatives :
y = a sin 3x + b cos 3x
dy/dx = 3a cos 3x - 3b sin 3x
d²y/dx² = - 9a sin 3x - 9b cos 3x
Next, you have to compare it :
let d²y/dx² = ky,
-9a sin 3x - 9b cos 3x = k(a sin 3x + b cos 3x)
-9(a sin 3x + b cos 3x) = k(a sin 3x + b cos 3x)
Therefore, k is equals to 9.
Answer:
point - slope form
y - 1 = 3 (x-0)
Step-by-step explanation:
<u><em>step(i):-</em></u>
Given points are (0,1) and (2,7)
The slope of the line


m =3
<u><em>Step(ii):-</em></u>
point -slope form
y - y₁ = m(x-x₁)
Equation of the straight line passing through the point (0,1) and having slope 'm' = 3
y - 1 = 3 (x-0)
y -1 = 3x
3x - y +1=0
Equation of the straight line passing through the point (0,1) and having slope 'm' = 3 is 3x -y +1=0
Answer:
4/25=0.16=16%
3/11=0.27=27%
Step-by-step explanation:
D because I answered it at school and it was correct