the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
Answer:
27
Step-by-step explanation:
first we can simplify by dividing by r

the r on the bottom of the fraction will cancel out one of the r's on top, this happens because anything divided by itself is 1, thus r divided by r is 1
finally we can evaluate when r =3,
9r = 9(3) = 27



then find y and plug that y value into one of the original equations to find x
Hope this helps!
Answer:
(5,3)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let the larger number = 6
Let the smaller number = 4
Ratio
The greater number = 6
The smaller number = 4
The ratio is 6/4 = 3/2
Isn't that a bit amazing? If you multiply 6 * 4 you get 24. You would think that that is the lowest common multiple. It isn't.
6: 3 * 2
4: 2 * 2
The lowest common multiple is one with 1 three and 2 twos.