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Inessa05 [86]
2 years ago
14

Find the slope of a line parallel to the given line. y=4/5x+5

Mathematics
1 answer:
xeze [42]2 years ago
3 0

Answer:

y = 4/5x

Step-by-step explanation:

Her ya go!

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Find the 13th term of the arithmetic sequence -3x – 1,42 + 4,112 + 9, ...
Strike441 [17]

Answer:

The 13th term is 81<em>x</em> + 59.

Step-by-step explanation:

We are given the arithmetic sequence:

\displaystle -3x -1, \, 4x +4, \, 11x  + 9 \dots

And we want to find the 13th term.

Recall that for an arithmetic sequence, each subsequent term only differ by a common difference <em>d</em>. In other words:

\displaystyle \underbrace{-3x - 1}_{x_1} + d = \underbrace{4x + 4} _ {x_2}

Find the common difference by subtracting the first term from the second:

d = (4x+4) - (-3x - 1)

Distribute:

d = (4x + 4) + (3x + 1)

Combine like terms. Hence:

d = 7x + 5

The common difference is (7<em>x</em> + 5).

To find the 13th term, we can write a direct formula. The direct formula for an arithmetic sequence has the form:

\displaystyle x_n = a + d(n-1)

Where <em>a</em> is the initial term and <em>d</em> is the common difference.

The initial term is (-3<em>x</em> - 1) and the common difference is (7<em>x</em> + 5). Hence:

\displaystyle x_n = (-3x - 1) + (7x+5)(n-1)

To find the 13th term, let <em>n</em> = 13. Hence:

\displaystyle x_{13} = (-3x - 1) + (7x + 5)((13)-1)

Simplify:

\displaystyle \begin{aligned}x_{13} &= (-3x-1) + (7x+5)(12) \\ &= (-3x - 1) +(84x + 60) \\ &= 81x + 59 \end{aligned}

The 13th term is 81<em>x</em> + 59.

3 0
3 years ago
Rewrite the equation in standard form y - 3 = 4(x - 3)
kumpel [21]

Answer:

y=4x-9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
4x^2-20=5 solve by using the square root property
riadik2000 [5.3K]

Step-by-step explanation:

4x^2 - 20 = 5

4x^2 -25 = 0

4x^2 = 25

2x = 5, or -5

x = 5/2 , or -5/2

7 0
3 years ago
Which of the following are equivalent to -7?
Scilla [17]
49/-7 and -21/3 are the only two equivalent to -7
3 0
3 years ago
A parking lot contains 100 cars , k of which happen to be lemons. we select m of these cars
Sunny_sXe [5.5K]
Given that a parking lot contains 100 cars, k of which happen to be lemons.

This is a conditional probability question.

Let event A be that a car is tested and event B be that a car is lemon.

The probability that a car is lemon is given by \frac{k}{100}

The probability that a car is tested is given by \frac{m}{100}

The probability that a car is lemon and it is tested is given by \frac{n}{m}

For a conditional probability, the probablility of event A given event B is given by:

P(A|B)= \frac{P(A\cap B)}{P(B)}

Therefore, the probability that a car is lemon, given that it is tested is given by.

P(lemon|tested)= \frac{P(lemon\, and\, tested)}{P(tested)}  \\  \\ = \frac{ \frac{n}{m} }{ \frac{m}{100} } = \frac{n}{m} \times \frac{100}{m} = \frac{100n}{m^2}
4 0
3 years ago
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