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Olin [163]
2 years ago
6

12 snakes have how many eyes altogether?

Mathematics
2 answers:
taurus [48]2 years ago
4 0

Answer:

24

Step-by-step explanation:

12 * 2 = 24

alexgriva [62]2 years ago
3 0

Answer:

24

Step-by-step explanation:

each snake has 2 eyes so you would do 12*2 which would then be 24

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Sampson has a list of items that are on sale to pick up at the store. The sale items are the following:
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the answer is A) Yes, Sampson's receipt is correct.

Step-by-step explanation:

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2 years ago
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Find the length of the third side. If necessary, write in simplest radical form.
Mazyrski [523]

Answer:

\boxed {\boxed {\sf 8}}

Step-by-step explanation:

This triangle has a small square, which represents a right angle. Therefore, we can use the Pythagorean Theorem.

a^2+b^2=c^2

Where <em>a</em> and <em>b </em> are the legs of the triangle and <em>c</em> is the hypotenuse.

In this triangle, 7 and √15 are the legs, because these sides make up the right angle. The unknown side is the hypotenuse, because it is opposite the right angle. So, we know two values:

a= 7 \\b= \sqrt{15}

Substitute these values into the formula.

(7)^2+(\sqrt{15})^2=c^2

Solve the exponents.

  • (7)²= 7*7=49

49+ (\sqrt{15})^2=c^2

  • (√15)²=√15*√15=15

49+15=c^2

Add.

64=c^2

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

\sqrt{64}=\sqrt{c^2} \\\sqrt{64}= c\\8=c

The third side length is <u>8.</u>

6 0
3 years ago
Read 2 more answers
Which compound inequality can be used to solve the inequality 3x+2&gt;7
kipiarov [429]

Answer:

3x + 2 < –7 or 3x + 2 > 7

3 0
2 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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