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faltersainse [42]
4 years ago
10

Factor 2z to the second power +3z-9

Mathematics
1 answer:
kozerog [31]4 years ago
5 0
The answer is (2z-3)(z+3)
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In the image below, 10 is the long leg of the 30-60-90 triangle.<br><br><br> True or false?
never [62]

The measure of the angle between the hypotenuse and the <em>short</em> leg is 60° and we can conclude that the side with length 10 is not the <em>long</em> leg of the 30 - 60 - 90 <em>right</em> triangle. (Right choice: False)

<h3>Is the length of a known arm in a 30 - 60 - 90 right triangle the long arm?</h3>

In accordance with geometry, the length of the <em>long</em> arm of a 30 - 60 - 90 <em>right</em> triangle is √3 / 2 times the length of the hypotenuse, the length of the <em>short</em> arm is 1 / 2 times the length of the hypotenuse and the length of the <em>long</em> arm is √3 times the length of the arm.

Thus, the measure of the angle between the hypotenuse and the <em>short</em> leg is 60° and we can conclude that the side with length 10 is not the <em>long</em> leg of the 30 - 60 - 90 <em>right</em> triangle. (Right choice: False)

To learn more on right triangles: brainly.com/question/6322314

#SPJ1

3 0
2 years ago
Find the point of the intersection for the given systems y=x^2+1 and y=x+1
mario62 [17]

set them equal to each other

x²+1=x+1

minus 1 from both sides

x²=x

minus x both sides

x²-x=0

factor

x(x-1)=0

set each to 0

x=0


x-1=0

x=1


subsitute back to find y values

y=x+1, y=0+1, y=1, one point is (0,1)

y=x+1, y=1+1, y=2, another point is (1,2)


the 2 points of intersection are (0,1) and (1,2)

7 0
3 years ago
In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th
ehidna [41]

Question:

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th birthday, 25% married by their 20th birthday, and 76% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by the following ages? (Enter your answers to four decimal places.) (a) 18 years of age (b) 20 years of age (c) 30 years of age

Answer:

A.) 0.0064

B.) 0.0625

C.) 0.5776

Step-by-step explanation:

Given the following :

Married by 18th birthday = 8% = 0.08

Married by 20th birthday = 25% = 0.25

Married by 30th birthday = 76% = 0.76

In a family with two(2) daughters :

P(First daughter will be married by 18) = 0.08

P(second daughter will be married by 18) = 0.08

P(1st and 2nd married by 18) = (0.08×0.08) = 0.0064

B.)

P(First daughter will be married by 20) = 0.25

P(second daughter will be married by 20) = 0.25

P(1st and 2nd married by 20) = (0.25×0.25) = 0.0625

C.)

P(First daughter will be married by 30) = 0.76

P(second daughter will be married by 30) = 0.76

P(1st and 2nd married by 30) = (0.76×0.76) = 0.5776

6 0
3 years ago
Baker made 5 pounds of icing. He used 4/9 of the icing to decorate. How much did he have left over?
Elena L [17]
If the baker made 5 pounds of icing and used 4/9 of the icing to make decorations, then he used:

5 * 4/9 =
= 20/9 =
= 2 2/9 [of icing]

To find out how much he has left over, we just need to substract 2 2/9 from 5:

5 - 2 2/9 =
= 3 - 2/9 =
= 2 7/9

Answer: The baker has <u>2 7/9</u> of the icing left.
6 0
3 years ago
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8 0
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