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mart [117]
3 years ago
12

What is the solution to this equation?

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

\large \boxed{\text{B. x = 8}}

Step-by-step explanation:

\begin{array}{rcll}x - 12 & = & -4 & \\x - 12 + 12 &= & -4 + 12 & \text{Added 12 to each side}\\x & = & \mathbf{8} & \text{Simplified}\\\end{array}\\\large \boxed{\mathbf{x = 8}}

Check:

\begin{array}{rcl}8 - 12 & = & -4\\-4 & = &-4\\\end{array}

OK.

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