A trampoline has an area of 49 times pie square feet. what is the diameter of the trampoline?

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

3 years ago

Find the variable x in the figure if AB ll CD ll EF where c and d are the midpoints of AE and BF.

dangina [55]

CD is called the middle base and is equal to :(AB + EF)/2

CD = (AB + EF)/2

4x = [(x²+10) + (8-x)]/2

8x = x²+10+8-x

8x= x²-x+18
x²-9x+18 = 0

x' = [-b+√(b²-4.a.c)]/2a & x" = [-b-√(b²-4.a.c)]/2a

x'= 6 and x" = 3, So we have2 values of x

5 0

3 years ago

You have $40 in your wallet, but you do not want to spend all of it. You want to have at least some money left. You find a shirt

lara31 [8.8K]

Answer:

35

Step-by-step explanation:

40-5=35

35 is left over so it is yout leftover change or money

6 0

3 years ago

Given that El bisects ZCEA, which statements must be

Alexxx [7]

Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.

(See attachment below for the figure)

m∠CEA = 90°

m∠CEF = m∠CEA + m∠BEF

m∠CEB = 2(m∠CEA)

∠CEF is a straight angle.

∠AEF is a right angle.

Answer:

m∠CEA = 90°

∠CEF is a straight angle.

∠AEF is a right angle

Step-by-step explanation:

Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.

Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.

Thus, the three statements that must be TRUE are:

m∠CEA = 90°

∠CEF is a straight angle.

∠AEF is a right angle

3 0

2 years ago

AC = Round your answer to the nearest hundredth. A 5 35 B C

baherus [9]

Answer:

2.87 = AC

Step-by-step explanation:

Since this is a right triangle we can use trig functions

sin theta = opp / hyp

sin 35 = AC /5

5 sin 35 = AC

2.867882182= AC

To the nearest hundredth

2.87 = AC

8 0

3 years ago