Answer:
D
Step-by-step explanation:
Since BD and AE are parallel lines, then
∠BDC = ∠AED ( corresponding angles ), thus
4x - 5 = 97 - 2x ( add 2x to both sides )
6x - 5 = 97 ( add 5 to both sides )
6x = 102 ( divide both sides by 6 )
x = 17, hence
∠AED = 97 - 2x = 97 - (2 × 17) = 97 - 34 = 63°
∠BDE and ∠AED are same side interior angles and are supplementary, thus
10y - 3 + 63 = 180
10y + 60 = 180 ( subtract 60 from both sides )
10y = 120 ( divide both sides by 10 )
y = 12 → D
M<A = m<C = 53
answer is B. 53
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2x = 8
x = 4
answer
D. 4
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y = 3x (1)
y + 12 = 6x so y = 6x - 12 (2)
from (1) and (2) you haev
3x = 6x - 12
3x = 12
x = 4
y = 4x = 4(3) = 12
answer
C. y = 12
(7x^2 + 6x + 5 ) - (x - 5)^2
(7x^2 + 6x + 5 ) - (x^2 - 10x + 25)
6x^2 + 16x - 20 is the answer
Cos x = 1/√10
sin x = √( 1 - 1 /10 ) = √9/10 = - 3/√10 ( because x is in Q IV )
cot 2 x = cos 2 x/sin 2x = ( cos²x - sin²x)/ (2 sinx cosx ) =
= ( 1/10 - 3/10 )/(2 * (-3/√10)*1/√10)= (- 8/10 ) / (-6/10 ) = 8/6 = 4/3
