Answer:
BDC 37°
CDE 143°
FDE 37°
FDA 90°
with a hope, this helps you!
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
the lenght of the picture is 14
To find the mean add all the numbers up then divide by how many numbers you have.
-36+(-25)+12+(-4)+18= (-35)
there are a total of five numbers so divide by 5
(-35)/5=(-7)
answer -7
Answer:
You should advise him to buy preferred stock.
Step-by-step explanation:
