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Alexxandr [17]
3 years ago
14

How to find 75% of £36

Mathematics
2 answers:
Over [174]3 years ago
8 0
1. £36 times 3
2. £108 / 4
3 £27
aksik [14]3 years ago
3 0
50% = 18
10% = 3.6
10% = 3.6
5% = 1.8
= £27

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Solve the proportional equation below 6/2=(v-8)/(v-3)
goldfiish [28.3K]

½ = v; multiply the divisor to remove the variable from the denominator.

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3 years ago
HELP ME PLEASE HURRY: Wade has claims that quadrilateral ABCD is a square because he has found that all four sides are congruent
RUDIKE [14]

Answer:

At first we should know that:

<u>The properties of the square are:</u>

  1. It has four equal sides.
  2. All angles are right angles or equal to 90º.
  3. The sum of its all angles is 360º
  4. It has two pairs of perpendicular lines.
  5. It has two pairs of parallel lines.

<u>The properties of Rhombus</u>

  1. It has equal four sides.
  2. The opposite sides are of the same length.
  3. It has two acute angles and two obtuse angles.
  4. The sum of its all angles is 360º
  5. It has zero pairs of perpendicular lines.
  6. It has two pairs of parallel lines.

So, Wade is incorrect because the quadrilateral may be <u>Rhombus</u>

And the quadrilateral to be a square, she needs to show that It has two pairs of perpendicular lines.

6 0
3 years ago
A number times 45 decreased by 12 is no more than 117​
Kay [80]

Answer: n*4512 is less than or equal to 117

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5 0
3 years ago
If it takes 10 machines 10 minutes to make 10 widgets, how long would it take 50 machines to make 50 widgets? minutes
Allushta [10]
If it takes 10 machines 10 minutes to make 10 items, I would assume it would take 50 machines 50 minutes to make 50 items. Hope this helps :)
5 0
3 years ago
Read 2 more answers
Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20
Naily [24]

Answer:

\displaystyle y = x^{-\frac{2}{3}}

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. \log(pq)=\log p+\log q

2. \displaystyle \log_pq=\frac{1}{\log_qp}

3. \displaystyle \log p^q=q\log p

We are given the equation:

\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }

Applying the second property:

\displaystyle  \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}

Substituting:

\displaystyle \log_{2}(x) = 3\log_{2}(xy)

Applying the first property:

\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))

Operating:

\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)

Rearranging:

\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)

Simplifying:

\displaystyle -2\log_{2}(x) =3\log_{2}(y)

Dividing by 3:

\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}

Applying the third property:

\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)

Applying inverse logs:

\boxed{y = x^{-\frac{2}{3}}}

7 0
3 years ago
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