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Anna35 [415]
3 years ago
8

Solve the system. x+y=7 y-z=4 X + z = 3

Mathematics
1 answer:
jeyben [28]3 years ago
4 0

Answer:

X=2

Y=5

Z=1

Explanation:

2+5=7

5-1=4

2+1=3

Brainliest Pls

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At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye
Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that \mu = 3125

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that n = 9, X = 2915, s = 585

What is the test statistic needed to evaluate the claim?

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}

t = -1.08

The test statistic needed to evaluate the claim is t = -1.08.

6 0
2 years ago
Using the formula r=d/t where d is the distance in miles, r is the rate and t is the time in hours at which rate must you travel
valentina_108 [34]

r =  \frac{337.5}{4.5}  \\ r = 75
the answer is c-75mph
6 0
3 years ago
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You have 16 socks in your drawer. 4 are black, 6 are white, 4 are blue, and 2 are gray. Suppose you randomly choose a sock, repl
Alinara [238K]

Answer:

11/32

Step-by-step explanation:

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simplify and solve

4 0
3 years ago
PLEASE HELP Show all Your work 25 points will give brainly
julsineya [31]

Answer:

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Step-by-step explanation:

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Vsevolod [243]

Answer:

The correct answer is 101.

Step-by-step explanation:

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The lower quartile of the data set for the blood glucose levels of 10 individuals is given by the mid value of the first five terms 88, 97, 101, 104 and 104.

Thus the mid value of this first half \frac{5+1}{2}  th term is 101. Thus the lower quartile of the data set is 101.

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