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2 years ago

Solve the system. x+y=7 y-z=4 X + z = 3

Mathematics

1 answer:

jeyben [28]2 years ago

4 0

Answer:

X=2

Y=5

Z=1

Explanation:

2+5=7

5-1=4

2+1=3

Brainliest Pls

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Eddi Din [679]

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2 years ago

A customer bought a car and paid $1,080 in sales tax. The sales tax rate is 6%. What was the price of the car before the tax?

Helga [31]

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3 years ago

The ratio of teachers to male students to female students in a school is 3:17:18 if the total number of students in the school i

Artist 52 [7]

Answer: 54

Step-by-step explanation:

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1 year ago

At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl

Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

$n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.$

Let 'p' represents the number of students who take all the three languages, then

$n(A\cap B\cap C)=p.$

Also,

$n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).$

From here, we get after subtracting equation(c) from (b) that

$n(A\cap B)=n(A\cap C)=14.$

Therefore,

$p=14+14-24=4,$ and from equation (a), we find

$n(B\cap C)=24-14=10.$

Thus,

$n(A\cap B\cap C)=4$ and

$n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.$

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

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2 years ago

Solve 64-31-3.64 + 22 = 38

professor190 [17]

Answer:

51.36=38

Step-by-step explanation:

You apply all these together:

64-31-3.64 + 22=51.36

51.36=38

4 0

2 years ago