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3 years ago

. Find the value of x. a. 22.5 b. 18.5 c. 18 d. 12

Mathematics

1 answer:

Tasya [4]3 years ago

5 0

Answer:

Picture, or question? I will edit once I see the question!

Step-by-step explanation:

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The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

2 years ago

Suppose the average commute time of your employees is unknown. The standard deviation of their commute time is estimated as 22.8

nexus9112 [7]

Answer:

96 employees

Step-by-step explanation:

Given that the standard deviation = 22.8

The width in the question = 12

We solve for the margin of error E.

E = width / 2

= 12/2 = 6

At 99%

Alpha = 1-0.99

= 0.01

Alpha/2 = 0.01/2 = 0.005

Z0.005 = 2.576

Sample size n

= ((2.576x22.8)/2)²

= 95.8

= 96

The number of employees is 96

Thank you!

6 0

2 years ago

In a grocery store, a bag of sweets marked for $5 was sold at a discount of 10%. What was the selling price for the bag of sweet

kumpel [21]

The correct answer is 0.5.

4 0

2 years ago

Find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

Flauer [41]

Answer:

The coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

Step-by-step explanation:

We need to find the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1)

The midpoint of line segment can be found using formula:

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We have $x_1=14, y_1=-8, x_2=12, y_2=-1$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\Midpoint=(\frac{14+12}{2},\frac{-8-1}{2})\\Midpoint=(\frac{26}{2},\frac{-9}{2})\\Midpoint=(13,\frac{-9}{2})$

So, the coordinates of the midpoint of a line segment with the given endpoints (14,-8), (12,-1) are $\mathbf{(13,\frac{-9}{2})}$

4 0

2 years ago

What is the least common multiple of 2, 6, and 12?

Debora [2.8K]

Answer:

The LCM of 2,6,12 2 , 6 , 12 is 2⋅2⋅3=12 2 ⋅ 2 ⋅ 3 = 12 .

Step-by-step explanation:

4 0

2 years ago