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den301095 [7]
3 years ago
11

Consider cases where the number of withholding allowances is less than 6. Which will cause the amount of federal income tax with

held to increase?
a.

Gross pay stays the same and withholding allowances increase.


b.

Gross pay increases by more than $20 and withholding allowances stay the same.


c.

Gross pay increases by more than $20 and withholding allowances increase.


d.

Gross pay decreases by more than $20 and withholding allowances stay the same.
Mathematics
2 answers:
KIM [24]3 years ago
8 0

Consider cases where the number of withholding allowances is less than 6.

The amount of federal income tax withheld will increase if the

1. Gross pay increases and withholding allowances remains the same or

2. Gross pay remains the same and withholding allowances decreases

Option B is correct. The amount of federal income tax withheld will increase when Gross pay increases by more than $20 and withholding allowances stay the same

Hope this helps..!!

Thank you :)

Alina [70]3 years ago
8 0

Gross pay increases by more than $20 and withholding allowances stay the same. hope it helps 100% Sure that is correct
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A certain radioactive material decays in such a way that the mass in kilograms remaining after t years is given by the function
Angelina_Jolie [31]

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7 0
1 year ago
diagrams are not drawn to scale. do numbers 10 and 12. i only care about the answers &amp; the steps to get the answers. pls don
Stella [2.4K]

10. from the question; the circle theorem obeyed is "angled formed by semi-circle"

The angle formed in a semicircle is 90 degrees, hence

m\angle XYZ=90^{\circ}

This gives

m\angle YXZ\text{ + m}\angle YZX\text{ = 90}

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\begin{gathered} m\angle YXZ\text{ = 2x + 8} \\ m\angle YZX\text{ = 5X - 2} \end{gathered}

Substituting values we get

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3 0
1 year ago
Please help me with this
Ne4ueva [31]

Answer:

Option c

Step-by-step explanation:

A system of equations are given to us. And we need to solve them . The given system is

\begin{cases} y = 2x - 3\dots 1 \\ y = x^2 - 3\dots 2 \end{cases}

We numbered the equations here . Now put the value of equation 1 in equation 2 that is substituting y = 2x - 3 in eq. 2 .

\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

We got two values of x as 0 & 2 . Alternatively substituting these values we have ,

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Thefore the required answer is ,

\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

4 0
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