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dmitriy555 [2]
3 years ago
7

The line with equation a + 4b = 0 coincides with the terminal side of an angle θ in standard position and cos θ>0 . What is t

he value of sinθ ?
Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

Answer:

\frac{-1}{\sqrt{17} }

Step-by-step explanation

We have given that equation of line a+4b=0

⇒4b= -a

⇒b= \frac{-a}{4}

slope of line = tan\theta =\frac{P}{B}= \frac{-1}{4}

⇒ tan\theta is negative therefore it lies into 4th quadrant

By, Pythagoras theorem H^2=P^2+B^2

by putting value of P= -1 & B=4

the value of H=\sqrt{17}

with the given condition cos\theta>0

i.e. \theta∈ (3π/2, 2π)

now, sin\theta= \frac{P}{H}= \frac{-1}{\sqrt{17}}



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