The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.
We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.
Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.
Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.
19.5 feet + 19.5 feet = 39 feet
Therefore, the area of Noshi's desk is 39 feet.
Hope this helps! :)
Ok then um so ya ok thx for the points though
11. Similar 1/2
12. Similar 2
13. no
14. no
15. No, they are not congruent because rectangles do not have equal sides, so the length of one triangle could be longer than the other and the width ozone can be shorter than the other.
16. Yes
You do 4/1 divided by 2/9
4 2
_ divided by _
1 9
Equals 18
(You have to multiply by the reciprocal)
4/1 times 1/4
And
2/9 times 1/4
Hope I helped!!!
X + y + z = 2
x - y + 5z = 6
cancelando +y com -y:
x + z = 2*(-5)
x + 5z = 6
-5x -5z = -10
...x +5z = 6
---------------------
-4x = -4 *(-1)
4x = 4
x = 4/4
x = 1
x + z = 2
1 + z = 2
z = 2 - 1
z = 1
x + y + z = 2
1 + y + 1 = 2
2 + y = 2
y = 2 - 2
y = 0
S: {x, y, z} = {1, 0, 1}
