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Fantom [35]
3 years ago
8

Find the missing factor. Does anybody know the answer 8b*2+7b-1= (b+1) ( )

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0

Answer:

8b^2+7b-1=(b+1)(8b-1)

The missing factor is: (8b-1)

Step-by-step explanation:

Given expression:

8b^2+7b-1=(b+1)(_-)

To find the missing factor of the given expression.

Solution:

In order to factor the given term, we will split the middle term into two terms such that the product of the two terms is equal to the product of the first and last term of the expression.

The product of first and last term for the expression is = (8b^2)(-1)=-8b^2

The middle term = 7b which can be split into  (8b-b) as their product = -8b^2

Thus, the expression can be rewritten as:

⇒ 8b^2+8b-b-1

We will factor in pairs by taking GCF.

⇒ 8b(b+1)-1(b+1)

Factoring the whole expression by taking the common factor.

⇒ (b+1)(8b-1)

Thus, the missing factor is: (8b-1)

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Suppose that A = PDP^-1. Prove that det(A) = det(D). 6. Suppose that A and B are nxn matrices that can be diagonalized with the
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Answer:

a) The main idea to solve this exercise is to use the identity \det(AB)=\det(A)\det(B), where A and B are two square matrices.

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Givens

x + y = 2

x - y = 6

Solution

Just add the two equations together. The y's will drop out.

x + y = 2

<u>x - y = 6 </u>             Add

2x = 8                 Divide by 2

2x/2 = 8/2          Combine

x = 4                   Substitute x = 4 into the top equation

x + y = 2

4 + y = 2             Subtract 4 from both sides

4-4+y=2-4          Combine

y = - 2    

Answer

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y = -2

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