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2 years ago

Y=4x+rx+6 solve for x

1 answer:

5 0

$y=4x+rx+6$

$y-6=4x+rx

$ $Subtract \ 6 \ from \ both \ sides$

$y-6=x(4+r)

 
$ $Factor \ out \ the \ common \ term \ x$

$\dfrac{y-6}{4+r} =x$ $Divide \ both \ sides \ by \ 4+r$

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he following data set shows the number of dogs counted in a local park each Saturday for 4 months. 33, 36, 31, 37, 37, 38, 31, 3

lana66690 [7]

General Idea:

To create a dot plot for a set of data we should list the data from lowest to greatest number. Then create a number line which covers all the numbers given in the data. We need to plot number of circles one above as many times based on the frequency of the data.

Applying the concept:

33, 36, 31, 37, 37, 38, 31, 37, 35, 31, 38, 32, 36, 33, 38

Listing the data in ascending order we get

31, 31, 31, 32, 33, 33, 35, 36, 36, 37, 37, 37, 38, 38, 38

We need to plot three circles above 31, one circle above 32, two circles above 33, one above 35, two above 36, three above 37, and three above 38.

Conclusion:

Out of the four options, the correct option is B because that is the only dot plot representing the given set of data.

7 0

3 years ago

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4/5 as an equivalent fraction in 3 different forms.

levacccp [35]

Answer:

Equivalent fraction of ⅘:

$\frac{4}{5} = \frac{8}{10} = \frac{12}{15} = \frac{16}{20}$

8 0

2 years ago

Solve for x!!!!!.....

mojhsa [17]

X=10.5
8/6=14/x
Cross multiply
8x=84
Divide 8 to both sides
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3 0

2 years ago

Find the area of an isosceles trapezoid, if the lengths of its bases are 16 cm, and 30 cm, and the diagonals are perpendicular t

Klio2033 [76]

For this case we have:
a = 30 cm
c = 16 cm
We look for the length of the diagonal:
d = x + y
Where,
For x:
a ^ 2 = x ^ 2 + x ^ 2
x = a / root (2) = 30 / root (2) = 21.2132 cm
For y:
c ^ 2 = y ^ 2 + y ^ 2
y = c / root (2) = 16 / root (2) = 11.3137 cm
The diagonal is:
d = x + y
d = 21.2132 + 11.3137
d = 32.5269 cm
Then, the height is:
h = h1 + h2
For h1:
h1 = root (x ^ 2 - (a / 2) ^ 2) = root ((21.2132) ^ 2 - (30/2) ^ 2)
h1 = 15 cm
For h2:
h2 = root (y ^ 2 - (c / 2) ^ 2) = root ((11.3137) ^ 2 - (16/2) ^ 2)
h2 = 8 cm
Finally:
h = h1 + h2
h = 15 + 8
h = 23 cm
Then, the area is:
A = (1/2) * (a + c) * (h)
A = (1/2) * (30 + 16) * (23)
A = 529 cm ^ 2
Answer:
the area of an isosceles trapezoid is:
A = 529 cm ^ 2

4 0

2 years ago

What is the equation of the given line? (-4,3) (2,-3)

WARRIOR [948]

Answer:

y=-x-1

Step-by-step explanation:

8 0

3 years ago

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