Evaluate x 1 - x -1 + x 0 for x = 2 a) 0 b)1/2 c)1 1/2 d)2 1/2

Mathematics

1 answer:

laiz [17]2 years ago

6 0

To solve, substitute the values of x with 2.
(2)^1 - (2) - 1 + 2^0 = 0.
The answer would be a)

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Can someone help me find the area of the following figure

ExtremeBDS [4]

1. The area of the full rectangle is 21 * 28 = 588. We will need this later.

Like you drew, there is an imaginary triangle missing. We can find the dimensions of it by subtracting from the given information. The shorter leg of it is 21 - 12 = 9, the longer leg is 28 - 14 = 14.

Now we find the area of the triangle. Area of a triangle is 1/2 * base * height. So 1/2 * 9 * 14 = 1/2 * 126 = 63.

Now we do the full area of 588 minus the area of the missing triangle piece.

588 - 63 = 525 ft²

2. Do the area of the rectangle and then this time add on the area of the triangle. 7 * 15 = 105. Area of the triangle = 1/2 * 2 * 7 = 1/2 * 14 = 7.

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6 0

3 years ago

Find the perimeter and the area of each shape. Give your answer as a completely simplified exact value in terms of π (no approxi

nydimaria [60]

Answer:

Circumference: 12π + 8 cm,

Area: 48 ( cm )^2

Step-by-step explanation:

This figure is composed of circles, squares, and semicircles. As you can see, the squares indicate that each semicircle should have ( 1 ) the same area, and ( 2 ) the same length ( circumference ). It would be easier to take the circumference of the figure first, as it is composed of arcs part of semicircles the same length.

Circumference of 1 semicircle = $\frac{1}{2}$ ( πd ) = $\frac{1}{2}$ π( 4 ) = 2π ( cm )

Circumference of Figure (composed of 6 semicircles + 2 sides of a square),

We know that 6 semicircles should be 6 $*$ 2π, and as the sides of a square are equal - if one side is 4 cm, the other 3 are 4 cm as well. Therefore the " 2 sides of a square " should be 2

Circumference of Figure = 6 $*$ 2π + 2 = 12π + 8 ( cm )

_____________

The area of this figure is our next target. As you can see, it is composed of 3 semicircles, and the area of 3 semicircles subtracted from the area of 3 squares. Therefore, let us calculate the area of 1 semicircle, and the area of 1 square first.

Area of 1 semicircle = 1/2π $r^2$ = 1/2π $(2)^2$ = 2π ( cm ),