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2 years ago

Evaluate x 1 - x -1 + x 0 for x = 2 a) 0 b)1/2 c)1 1/2 d)2 1/2

Mathematics

1 answer:

laiz [17]2 years ago

6 0

To solve, substitute the values of x with 2.
(2)^1 - (2) - 1 + 2^0 = 0.
The answer would be a)

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Step-by-step explanation:

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m = slope

b = y intercept

y = -5/2x - 3

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Suzanne bought 6 paint sets. Each set contains the same number of brushes. She has 18 brushes. Write and solve an equation to de

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Answer:

Step-by-step explanation:

Given that:

The number of paint sets, Suzanne bought= 6

As each set contains the same number of brushes.

Let x be the number of brushes each set contains.

So, the total number of brushes in 6 sets = 6x.

It is given that the total number of brushes she has is 18, which is equals to 6x.

So, the required equation is

$6x=18$

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2 years ago

I really need help i don’t understand !!!!!!

inn [45]

Answer:

y+2 = -4/5(x-3)

Step-by-step explanation:

The point slope form of a line is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y - -2 = -4/5(x-3)

y+2 = -4/5(x-3)

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3 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

Viktor [21]

Answer:

Therefore $k= \frac{ln2 }{18}$ , A=184

Step-by-step explanation:

Given function is

$T(t)=230 -e^{-kt}$

where T(t) is the temperature in °C and t is time in minute and A and k are constants.

She noticed that after 18 minutes the temperature of the pie is 138°C

Putting T(t) =138°C and t= 18 minutes

$138=230 -Ae^{-k\times 18}$

$\Rightarrow -Ae^{-18k}=138-230$

$\Rightarrow Ae^{-18k}=92$ .....(1)

Again after 36 minutes it is 184°C

Putting T(t) =184°C and t= 36 minutes

$184=230-Ae^{-k\times 36}$

$\Rightarrow Ae^{-36k}=230-184$

$\Rightarrow Ae^{-36k}=46$ .......(2)

Dividing (2) by (1)

$\frac{Ae^{-36k}}{Ae^{-18k}}=\frac{46}{92}$

$\Rightarrow e^{-18k}=\frac{46}{92}$

Taking ln both sides

$ln e^{-18k}=ln\frac{46}{92}$

$\Rightarrow -18k =ln (\frac12)$

$\Rightarrow -18k= ln1-ln2$

$\Rightarrow k= \frac{ln2 }{18}$

Putting the value k in equation (1)

$Ae^{-18\frac{ln2}{18}}=92$

$\Rightarrow A e^{ln2^{-1}}=92$

$\Rightarrow A.2^{-1}=92$

$\Rightarrow \frac{A}{2}=92$

$\Rightarrow A= 92 \times 2$

⇒A= 184.

Therefore $k= \frac{ln2 }{18}$ , A=184

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2 years ago