Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.

1 answer:

8 0

Please: Use "^" to denote exponentiation: 2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2: x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

 x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).

Finally, solve for x: x = -2 plus or minus sqrt(10).

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Complete the square
isolate x terms
y=(x^2-14x)+53
take 1/2 of -14 and square it ((-7)^2=49
add plus and minus of that inside the parntehasees

y=(x^2-14x+49-49)+53
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3 years ago

Can someone please answer number 5?

Free_Kalibri [48]

Answer:

x=13

Step-by-step explanation:

since they are vertical angles, they equal each other so set both angles to have them equal each other to find x

$8x - 12 = 6x + 14$