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Zigmanuir [339]
3 years ago
12

A radio DJ frequently announces how much money is currently in a jackpot. Every day several randomly selected residents are call

ed and asked to identify the amount, and thereby win it. Those who keep track of the jackpot amount are most likely to be reinforced on a __________ schedule.
Mathematics
1 answer:
Fofino [41]3 years ago
6 0

Answer:

"Variable interval" is the right solution.

Step-by-step explanation:

  • A variable-interval timetable seems to be a fiber-reinforced routine where another sensitivity or reaction would be commended because an unanticipated or unstable transaction has taken place, which would be the exact reverse of either a fixed-interval routine.
  • The whole such schedule results in a slow or predictable, fairly constant targeted respondents.
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12+root of 35 divided by 2 + 12-2 root of 35 divided by 2
nadya68 [22]
So : 12+ \frac{\sqrt{35}}{2} + \frac{12-2 \sqrt{35} }{2}?

First, you want to bring everything together on the top of the fraction. 
12=24/2 so you can have \frac{24+ \sqrt{35}+12-2 \sqrt{35} }{2}

Add like terms -- 12 +24 = 36       \sqrt{35}-2 \sqrt{35} = \sqrt{35}

Now we are at \frac{24+ \sqrt{35} }{2} Which is the lowest possible simplified version while remaining at exact value. 

Feel free to check my math! I kinda did this off the top of my head. 
8 0
3 years ago
-5x-12=18 solve for x ty
emmasim [6.3K]

Answer:

<h2>X=-6</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • equation
  • PEMDAS
<h3>let's solve:</h3>
  1. add 12 to both sides:-5x-12+12=18+12=>-5x=30
  2. divide both sides by-5:-5x/-5=30/-5
  3. therefore x=-6
7 0
3 years ago
Read 2 more answers
A dormitory has n students, all of whom like to gossip. one of the students hears a rumor, and tells it to one of the other n −
Alekssandra [29.7K]

Answer:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

Step-by-step explanation:

From the question, we have the following condition:

p_1=p_2=1,\:and\:p_n=0

We know that each student who hears the rumor tells it to a student picked at random from the dormitory (excluding, of course, himself/herself and the person from whom he/she heard the rumor)

The 3rd student can therefore tell the rumour to n-2 students but only n-3 will accept it.

\implies p(3)=\frac{n-3}{n-2}

Consequently, the 4th student must not tell the 1st and second students.

\implies p(4)=\frac{n-3}{n-2}\times \frac{n-4}{n-2}

We can rewrite this to observe a pattern:

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^2}

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^{4-2}}

\implies p(r)=\frac{(n-3)(n-4)(n-5)...(n-r)}{(n-2)^{r-2}}

Hence, the probability that the rumor is told r times without coming back to a student who has already is:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

See attachment for complete question

4 0
3 years ago
What is the product3(x)^5(2x^2+4x+1)
ryzh [129]

Answer: 6x^7+ 12x^6+ 3x^5

Hope that helped

4 0
3 years ago
On a cordinat grid point n is at -2 4 and point a it at 6 4 the distance in units between n and s is
UkoKoshka [18]

Answer:

Its 7

Step-by-step explanation:

7

6 0
3 years ago
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