Vertices (3,0),(-3,0) co-vertices (0,-5),(0,5)
transverse axis (line passing vertices) is on(or parallel to) x-axis then formula is
(x-h)^2/a^2 - (y-k)^2/b^2 = 1
..notice.. x^2 is on positive / y^2 is on negative
center (h,k) is midway between vertices = (0,0)
we have h = k = 0 and now formula is
x^2/a^2 - y^2/b^2 = 1
a is the distance from a vertex to center = 3
b is the distance from a co-vertex to center = 5
the formula is
x^2/3^2 - y^2/5^2 = 1 ... answer is the 1st
Answer:
if he wants to have $400000 on gis bank in 30 years at 4 %rate then he needs to deposit $15151.5 per month
Answer:
2
Step-by-step explanation:
HCF(55,99)= 11
- 55m-99=11
- 55m=110
- m=110/2
- m=2
