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seropon [69]
3 years ago
7

On a map, the length of a nature trail is 7.2 centimeters. If the scale is 1 centimeter to 25 kilometers, what is the actual len

gth of the trail? Round to the nearest tenth when necessary. HINT: Set up and solve as a proportion and find x.
Mathematics
2 answers:
levacccp [35]3 years ago
6 0

Given the scale is 1 cm to 25 km.

We have to find the length of the trail from centimeter to the nearest tenth of kilometer.

Let's take the length of the trail be x km.

The length of the trail given 7.2 cm. We will have to find the length in km.

We have to set it up as a proportion. So we can write the proportion as,

\frac{1}{25} = \frac{7.2}{x}

We have to cross multiply first. We will get,

(1)(x) = (7.2)(25)

x= (7.2)(25)

x = 180

So we have got the required length of the train in kilometer.

The actual length of the trail = 180km.

WARRIOR [948]3 years ago
5 0
1/25 = 7.2/x.....1 cm to 25 km = 7.2 cm to x km
cross multiply
(1)(x) = (7.2)(25)
x = 180 km <===
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liberstina [14]

Correct answer is A.

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

<h3>How to calculate the diameter?</h3>

If you know the radius of the circle, multiply by 2 to get the diameter. The radius is the distance from the center of the circle to the edge. For example, if the radius of a circle is 4 cm, then the diameter is 4 cm x 2 = 8 cm. If you know the circumference of the circle, divide by π to get the diameter.

<h3>Briefing:</h3>

The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction which is A.

The diameter of the circle is used for the square as l=2r therefore corresponds to the diameter, while for a hexagon r=r being the radius of the circle.

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I understand that the question you are looking for is:

Describe at least two differences between constructing an inscribed regular hexagon and constructing an inscribed square.

A) The diameter of the circle is used for the square construction, but the radius of the circle is used for the regular hexagon construction.

B) The radius of the circle is used for the square construction, but the diameter of the circle is used for the regular hexagon construction.

C) The square will need two arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

D) The square will need six arcs along the circle, but the hexagon will need two arcs above and two arcs below the diameter of the circle.

7 0
2 years ago
Staci is attending a music festival. The ticket to the festival costs $87.96 . Staci plans to purchase $30.00 t-shirts from the
mafiozo [28]

Step one: 200-87.96=112.04

Step two: 112.04÷30≈3.7

Step three: 3.7↔3

Answer: Staci can buy 3 shirts

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3 years ago
RHOMBUS The diagonals of rhombus ABCD intersect at E. Given that
schepotkina [342]

Answer:

<u>Question 11:</u>

\angle DAC = 53^\circ

\angle AED = 90^\circ

\angle ADC = 74

DB = 16

AE = 6.03

AC = 12.06

<u>Question 12:</u>

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

<u>Question 11</u>

Given

\angle BAC = 53^\circ

DE = 8

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): \angle DAC

Diagonal CA divides \angle DAB into 2 equal angles

i.e

\angle DAC = \angle BAC

So:

\angle DAC = 53^\circ

Solving (b): \angle AED

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

\angle AED = 90^\circ

Solving (c): \angle ADC

First, we calculate \angle ADE, considering \triangle ADE:

\angle ADE + \angle AED + \angle DAC = 180

\angle ADE + 90 + 53 = 180

\angle ADE + 143 = 180

\angle ADE = -143 + 180

\angle ADE = 37

To calculate \angle ADC, we have:

\angle ADC = 2*\angle ADE

\angle ADC = 2* 37

\angle ADC = 74

Solving (d): DB

From the rhombus

DB = DE +EB

Where

DE =EB

So:

DB = 8 + 8

DB = 16

Solving (e): AE

To do this we consider \triangle ADE

Using the tan formula

tan(\angle ADE) = \frac{AE}{DE}

\angle ADE = 37 and DE = 8

So:

\tan(37) = \frac{AE}{8}

AE = 8 * \tan(37)

AE = 6.03

Solving (f): AC

This is calculated as:

AC = AE + EC

Where

AE = EC

AC = 6.03 +6.03

AC = 12.06

<u>Question 12: Isosceles Triangle</u>

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

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3 years ago
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Dovator [93]

Answer:

1/10

Step-by-step explanation:

The value of 2 in 1,703,298 is 200.

The value of 2 in 3,932,574 is 2,000.

2,000 divided by 200 is 10.

Therefore, the 2 in 1,703,298 has 1/10 the value of the 2 in 3,932,574.

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3 years ago
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Answer:

tens of millions

Step-by-step explanation:

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