49x3= 147 so 10 reduction will make tim spend 137. 49x5= 245 so 20 reduction will make Craig spend 225. 225-147= 78 so Craig spends 78£ more than tim. All the offers state “X or Y” meaning it’s one or the other hence the ‘or’. Atleast that’s my interpretation of it.
Answer:
Step-by-step explanation:
Given equation :
Making the terms of 'x' to one side and constants to the other.
So, the value of 'x' is 29.
• So we know that.....
x represent bags of snack and y is bottles of water.
This equations shows the total amount and the cost of each water bottle and snack:
20.00 = 2.50x + 1.00y
Total: $20.00
Snack: $2.50
Water Bottle: $1.00
And this question shows the total items:
11 = x + y
Which there will be some snack + some water bottle = 11 items
—————————————————————
• Now I’m going to first solve for x, which is the amount of bags of snack.
I will use the equation, 11 = x + y.
(First, we’ll subtract y from both side, since we’re solving for x [UNDO])
11 = x + y
-y = - y
_______
11 - y = x —> so x is equal to 11 minus y.
—————————————————————
• Now we’re going to plug the 11 - y as x in the equation: 20.00 = 2.50x + 1.00y to solve for y.
20.00 = 2.50 (11 - y) + 1.00y
20.00 = 27.5 - 2.50y + 1.00y (Distributed)
20.00 = 27.5 - 1.50y (Combine like terms)
20.00 = 27.5 - 1.50y
-27.5 = -27.5 (Subtract -27.5 both side)
——————————
-7.5 = - 1.50y
-7.5 = -1.50y
—— ——— (Divide both side by -1.50)
- 1.50 = -1.50
5 = y
y is equals to 5, which means that there are 5 water bottles.
Now we know there are 11 items total and because there are 5 water bottles, there will be 6 bags of snacks. 11-5=6
—————————————————————
ANSWER:
They bought 6 bags of snacks! :)
Answer:
Step-by-step explanation:
The half life is the amount of time it takes a substance to decay to half of its original amount.
Since the radioactive substance has a half life of 1000 years, there will be half of it left after 1000 years.
So, the fraction that will be left after 1000 years is
Answer:
FG = 20 in
Step-by-step explanation:
∵ ABCD ≈ EFGH
∴ AD/EH = BC/FG
∵ AD = 45 in
∵ EH = 60 in
∴ BC = 15 in
∴ 45/60 = 15/FG
∴ FG = (60 × 15) ÷ 45 = 20 in
