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2 years ago

Ted says that 3 tenths multiplied by 100 equal 300 thousandth is he correct use a place value chart to explain

1 answer:

8 0

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If Judy has 4 blouses and 5 skirts, how many different outfits of a blouse and skirt can she wear?

Aloiza [94]

Answer:

Step-by-step explanation:

i think but not fur shure

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2 years ago

Read 2 more answers

Can someone please help me with all of these problems. They are a ton of them and they are due tomorrow. PLEASE AND THANK YOU

Masteriza [31]

15. $\frac{x}{5} - g = a$

Add "g" on both sides

$\frac{x}{5} = a +g$

Multiply 5 on both sides to get x by itself

x = 5(a + g)

x = 5a + 5g

18. a = 3n + 1

Subtract 1 on both sides

a - 1 = 3n

Divide 3 on both sides to get n by itself

$\frac{a - 1}{3} = \frac{a}{3} -\frac{1}{3}$ = n

21. M = T - R

Add "R" on both sides to get "T" by itself

M + R = T

24. 5p + 9c = p

Subtract "5p" on both sides

9c = p - 5p

9c = -4p

Divide 9 on both sides to get "c" by itself

c = $\frac{-4p}{9}$ or c = $\frac{-4}{9} p$

27. 4y + 3x = 5

Subtract "4y" on both sides

3x = 5 - 4y

Divide 3 on both sides to get "x" by itself

x = $\frac{5-4y}{3}$

x = $\frac{5}{3} -\frac{4y}{3}$

7 0

2 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago

If the numbers -2.5, -1.6, -3 1/10, - 1/10, and -0.5 were graphed on a number line, which would appear farthest to the left?

Leona [35]

Turn the question around.
If all the numbers were positive: 2.5, 1.6, 3 1/10, 1/10, and 0.5, which would be farthest to the right?

The fact is that the negative numbers are a reflection of the positive numbers.
Since 3 1/10 would be farthest to the right with positive numbers, -3 1/10 will be farthest to the left with the negative numbers.

7 0

2 years ago

A rod of aluminium has a mass of 575.4g and a volume of 210cm3

andreev551 [17]

Answer:

0.274g/cm^3

Step-by-step explanation:

density = mass / volume

so d = 575.4 / 210

d = 0.274g/cm^3

6 0

2 years ago