Answer:
the answer is 47
Step-by-step explanation:
Answer:
Maximum beat per minute for the lower 40% can be 77.
Step-by-step explanation:
Let z* be the z-score associated to the lower 40% bound. Then
P(z<z*)=0.4 By looking one tail z-table, we can find that z*=−0.253.
Let X be the maximum pulse rate among the pulse rates in the lower 40%. Then
z*=-0.253= where
- X is the maximum pulse rate of the lower 40%
- M is the mean resting pulse rates of all students at Adams High School (80 beats per minute)
- s is the standard deviation of resting pulse rates of all students at Adams High School (9 beats per minute)
-0.253= and we get X=(-0.253×9)+80=77.723
Since beats per minute can be positivive integer, maximum beat per minute for the lower 40% can be 77
82 percent of one hundred
X=-3 or x=3 Because yo have to reverse the inequality sign
Let the width be : x
length : (2x - 6)
(2x - 6) (x) = 2x square - 6x
2x square - 6x = 140
2x square - 6x - 140 = 0
if you use the cross method or calculator you’ll get :
( x - 10 ) ( x + 7) = 0
x = 10 or x = -7 ( reject because negative )
so we use x = 10.
width = 10
length = 2(10) - 6 = 14