Answer:
correct
Step-by-step explanation:
Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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Answer:
E. 5
Step-by-step explanation:
Let's rewrite the equation in the form of y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
2x + y = 5
y = -2x+5
M, the slope, is -2
<u>5, b, is the y-intercept</u>
See attached graph.
Answer:
No, the line does not pass (0,0).
No, the line does not pass (0,0)
Brainliest Appreciated!
Answer:
350
Step-by-step explanation:
since there are 2 zeros in "100", move the decimal over 2 places
