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Aliun [14]
2 years ago
8

Write the following expression without negative exponents and without parentheses.

Mathematics
1 answer:
jeka942 years ago
8 0

Answer:

1/10x * 1/10x

Step-by-step explanation:

Writing a term with negative exponents is the same as putting it in a fraction.

10x^-1 = 1/10x

so the expression would be

1/10x * 1/10x

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Given: Angle 2 is 65 degrees. What is the angle measurement of Angle 4. Explain the angle relationship used and show your work.
lesya [120]

Answer:

\angle 4 = 115^{\circ}

\angle 3 = 65^{\circ}

\angle 7 = 65^{\circ}

Step-by-step explanation:

Given

\angle 2 = 65^{\circ}

See attachment

Solving (a): \angle 4

To solve for \angle 4, we make use of:

\angle 2 +\angle 4 = 180^{\circ}

The relationship between both angles is that they are complementary angles

Make \angle 4 the subject

\angle 4 = 180^{\circ} - \angle 2

Substitute 65^{\circ} for \angle 2

\angle 4 = 180^{\circ} - 65^{\circ}

\angle 4 = 115^{\circ}

Solving (b): \angle 3

To solve for \angle 3, we make use of:

\angle 3 =\angle 2

The relationship between both angles is that they are complementary angles

\angle 3 = 65^{\circ}

Solving (c): \angle 7

To solve for \angle 7, we make use of:

\angle 7 = \angle 3

The relationship between both angles is that they are alternate exterior angles.

So:

\angle 7 = 65^{\circ}

7 0
2 years ago
2 1/3 divided by 1/4
babunello [35]

Answer:

20/3 or 6 2/3

Step-by-step explanation:

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3 years ago
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How do you write 6.5 in word form
Cerrena [4.2K]
6.5 six and five tenths
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3 years ago
8x - 12 = 15x - 4x
S_A_V [24]

Answer: Isolate the variable by dividing each side by factors that don't contain the variable. x=−4

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7 0
3 years ago
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GCSE 995381
nikdorinn [45]

Answer:

2.9 cm^2

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = \frac{1}{2}\times base \times height

We know that,

\sin \theta = \dfrac{P}{H}

\sin 30^\circ= \dfrac{P}{8}

P = \dfrac{8}{2}

P = 4\ cm

And

\cos \theta =\dfrac{B}{H}

\cos 30^\circ = \dfrac{B}{8}

B = \dfrac{8\times \sqrt{3}}{2}

B = 4\sqrt 3

Area of sector = \dfrac{\theta}{360^\circ}\times \pi r^2

Area of sector =  \dfrac{30^\circ}{360^\circ}\times \pi \times 8^2

                        = 16.75 cm^2

Area of triangle = \dfrac{1}{2} \times 4\sqrt 3 \times 4

                          = 13.85 cm^2

Area of shaded region = 16.75 - 13.85

                                      = 2.9 cm^2

7 0
2 years ago
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