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GalinKa [24]
3 years ago
11

What is the equation, in point-slope form, of the line

Mathematics
1 answer:
mixas84 [53]3 years ago
3 0

Answer:

y=-1x-1

Step-by-step explanation:

it should be this

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What is the common ratio for this geometric sequence 72,12,2,1/3,1/18
Olin [163]
It is b 6 is the answer
8 0
3 years ago
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(05.01 MC)
algol13

For the table, y = 9x.

 so the price of a short cake is $9


For the graph, y = 4x
so the price of a sweet bread is $4

9-4 = 5

 the short cake is $5 more than the sweet bread


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3 years ago
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Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i
kolezko [41]

Answer:

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

Step-by-step explanation:

Data given and notation

Data:    801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=811 represent the sample mean  

s=19.647 represent the standard deviation for the sample

n=5 sample size  

\mu_o =750 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses to be tested  

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:  

Null hypothesis:\mu = 750  

Alternative hypothesis:\mu \neq 750  

Compute the test statistic  

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943  

Now we need to find the degrees of freedom for the t distirbution given by:

df=n-1=5-1=4

What do you conclude?  

Compute the p-value  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{4}>6.943)=0.00226  

If we compare the p value and a significance level assumed \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.  

4 0
3 years ago
I WILL GIVE BRAINLIEST ANSWER!!!
Blababa [14]

Answer:

10 is unbiased

11 is biased

Step-by-step explanation:

10 is unbiased

11 is biased

Have an amazing day!

PLEASE RATE!!

7 0
2 years ago
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Gretchen made $56,750 last year. She paid $1,200 in student loan interest
iVinArrow [24]

Answer:

It's supposed to be Adjustments, but it's not on here so it's D.

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2 years ago
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