We are required to find the price of the first game
The price of the first game is $20
Given:
let
price of the first game = x
price of the second game = x + 50% of x
= x + 0.5x
= 1.5x
Price of the third game = 50% of 1.5x
= 0.5 × 1.5x
= 0.75x
Total cost of game = $65
<em>Total cost of game = price of the first game + price of the second game + Price of the third game</em>
65 = x + 1.5x + 0.75x
65 = 3.25x
divide both sides by 3.25
x = 65 ÷ 3.25
x = 20
Therefore, the price of the first game is $20
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5] The resultant vector will be:
<-6,5> and <6,-5>
=<(-6+6),(5-5)>
=<0,0>
the resultant vector is <0,0>
6] The value of x will be found as follows
tan θ=(opposite)/(adjacent)
θ=20°
hence:
tan 20=x/15
x=15tan20
x=5.4595~5.5 yd
