Answer:
3x+3
x+x+x+1+1+1 could also work but it's not simplified
I'm pretty sure my answers are right so please don't be upset if they aren't
What is the inter-quartile range of the given data set? 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25
Anastasy [175]
Hello!
First of all, we will want to find the median first. We have 11 values here, so we will want to find the 6th number in our data set to find the median. This median will cut our data in half.
15,16,17,18,19,20,21,22,23,24,25
To find the IQR, we need to find the median of each side of our data set now. We exclude the 20, and look for the median on each side. This would be the third number. This gives us our 1st and 3rd quartiles.
15,16,17,18,19,20,21,22,23,24,25
Now, to find the IQR, we subtract the first and third quartiles.
23-17=6
Therefore, our IQR is 
.
I hope this helps!
Answer:
Step-by-step explanation:
x/87 = 22/11
Multiply both sides by 87
x= 22/11 * 87
x= 1914/11
x= 174
Answer:
0.00665
0.006951
Step-by-step explanation:
If the first child is born with the affliction, there's a 0.05 probability that the second child will be born with the affliction. Which means there's a 0.95 probability that they won't.
The probability that the first child is born with the affliction but not the second is therefore:
P = 0.007 × 0.95
P = 0.00665
There's a 0.007 probability that the first child will be born with the affliction, which means there's a 0.993 probability that they won't. If the first child isn't born with the affliction, then the probability the second child will have it is 0.007.
So the probability that the first child is not born with the affliction and the second child is would be:
P = 0.993 × 0.007
P = 0.006951
Answer:
15) 3.2
17) 13.4
Step-by-step explanation:
To find the missing lengths, you need to use the Pythagorean theorem:
a² + b² = c²
In this form, "c" represents the length of the hypotenuse and "a" and "b" represent the lengths of the other two sides.
You are trying to find one of the side lengths (not the hypotenuse) in 15). To find the other length, you can plug the other values into the equation and simplify to find "b".
15) a = 4.1 c = 5.2
a² + b² = c² <----- Pythagreom Theorem
(4.1)² + b² = (5.2)² <----- Plug values in for "a" and "c"
16.81 + b² = 27.04 <----- Raise numbers to the power of 2
b² = 10.23 <----- Subtract 16.81 from both sides
b = 3.2 <----- Take the square root of both sides
You are trying to find the hypotenuse in 17). Since you have been given the lengths of the other sides, you can plug them into the equations and simplify to find "c".
17) a = 4.4 b = 12.7
a² + b² = c² <----- Pythagreom Theorem
(4.4)² + (12.7)² = c² <----- Plug values in for "a" and "b"
19.36 + 161.29 = c² <----- Raise numbers to the power of 2
180.65 = c² <----- Add
13.4 = c <----- Take the square root of both sides
