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Umnica [9.8K]
2 years ago
8

Give an example of a function that is integrable on the interval [-1,1], but not continuous on [-1,1]. explain.

Mathematics
1 answer:
Furkat [3]2 years ago
4 0
With an absolute value somewhere in the formula, you can create a discontinuous function.

how about f(x) = |x|/x

It jumps from -1 to +1 at x=0, yet it can be integrated on [-1,1]. The surface is 2.

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Step-by-step explanation:

<em>3^4</em>

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<em>3x3=9</em>

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<em>27x3=</em><em>81</em>

5 0
2 years ago
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Oduvanchick [21]

will she would have rode 4 3/5 miles in all.

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3 0
2 years ago
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Neporo4naja [7]

Answer:

2 times as long

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6 0
3 years ago
What is the solution to 2sin^(2)x+sinx+1=0
Alexus [3.1K]
Well you can try rewriting it to this

answer is   d  270

first start of by factoring  and subtracting the 1 into the right side

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so then you look in your unit circle and find what coordinate equals -1 in terms of sin x 

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3 years ago
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7 0
2 years ago
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