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Brilliant_brown [7]
3 years ago
12

In a symmetric and​ bell-shaped distribution, the​ mean, median, and mode are the same.

Mathematics
1 answer:
lidiya [134]3 years ago
7 0
The answwer to your question  is D

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Will mark brainlist if its right
pickupchik [31]

Answer: S<\-2

Hope i was some help.

Step-by-step explanation: sorry I can’t put the right sign my keybored won’t let me but you know what it stands for.

3s+6s</-5(s+2)

start off with -5(s+2) you multiply -5 with s and it is -5s then you do the same for +2 take -5 and multiply by +2 pos times a neg is always a neg so it’s -10.

3s+6<\-5s-10

So you have to get rid of the -5s so your going to do the inverse which is add 5 to -5 and it will get rid of -5s but then you have to add 5 to 3s and that will be 8s.

8s+6</-10

Now your going to get rid of the +6 and to do that you do the inverse you subtract 6 and it will get rid of it now you have to do the same for -10 so you will subtract 6 to -10 and that will equal -16.

Now you have to divide!

8s/8 </ -16/8

And it should equal s <\-2

3 0
3 years ago
Helpppppppppppppppppppppppppppp me
dalvyx [7]

I believe it's the last one

sorry if it's not the right one

5 0
3 years ago
The table represents what type of function
Luba_88 [7]

Answer

The function is x3

3 0
3 years ago
Read 2 more answers
What is the equation for y=-x+6 of X and Y?<br> -6, -3, 2, 4, 7
Ann [662]
Y=-x+6
Try -6 on X, -(-6)+6=12... wrong
Try -3 on X, -(-3)+6=9... wrong
Try 2 on X, -2+6=4... correct, you got X=2, Y=4
Try 4 on X, -4+6=2... correct, you got X=4, Y=2
Try 7 on X, -7+6=1... wrong
7 0
3 years ago
Use the rectangle hexagon with side length 10 meters to fill in the missing information
Vlada [557]

Answer:

A_h=150\sqrt{3}\ m^2

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

x=5 m

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

\theta=360/12=30^o

Now we have \theta, the height of the triangle y is easily found by

\displaystyle tan30^o=\frac{x}{y}

Solving for y

\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}

The value of z can be found by using

\displaystyle sin30^o=\frac{x}{z}

\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10

The area of the triangle is

\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}

The area of the hexagon is 12 times the area of the triangle, thus

\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}

\boxed{A_h=150\sqrt{3}\ m^2}

6 0
3 years ago
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