Question

Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4).

Answer 1

Intercept form is: y = a(x - p)(x - q)  

It is given that:  p = 14, q = -6, x = 14, y = 4

4 = a(14 - 12)(14 - (-6))

4 = a(2)(20)

4 = 40a

$\frac{4}{40} = \frac{40a}{40}$

$\frac{1}{10} = a$

Answer: y = $\frac{1}{10}$(x - 14)(x + 6)