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iVinArrow [24]
3 years ago
9

Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4).

Mathematics
1 answer:
xenn [34]3 years ago
6 0

Intercept form is: y = a(x - p)(x - q)  

It is given that:  p = 14, q = -6, x = 14, y = 4

4 = a(14 - 12)(14 - (-6))

4 = a(2)(20)

4 = 40a

\frac{4}{40} = \frac{40a}{40}

\frac{1}{10} = a

Answer: y = \frac{1}{10}(x - 14)(x + 6)



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For each of these problems, remember SOH-CAH-TOA.

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Cosine = adjacent/hypotenuse

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a_n = a_1 + (n - 1)d

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