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Svetllana [295]
3 years ago
6

What is the percent of increase from 6 to 9? Write your answer using a percent sign (%)

Mathematics
2 answers:
vladimir1956 [14]3 years ago
7 0

Answer:

50% increase

Step-by-step explanation:

Neporo4naja [7]3 years ago
6 0

Answer:

<em>The percent of increase from 6 to 9 is 50%</em>

Step-by-step explanation:

<u>Percentages</u>

To calculate the percentage increase:

Work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number.

Divide the increase by the original number and multiply the answer by 100.

We are required to find the percent increase from 6 to 9. Here: New number=9, Original number = 6

Increase = 9 - 6 = 3

Divide 3 by 6 and multiply the answer by 100:

3 / 6 * 100 = 50%

The percent of increase from 6 to 9 is 50%

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3 years ago
CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars
velikii [3]

Answer:

P(939.6 < X < 972.5) = 0.6469

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars.

This means that \mu = 965, \sigma = 113

Sample of 57:

This means that n = 57, s = \frac{113}{\sqrt{57}} = 14.97

Find the probability that a single randomly selected policy has a mean value between 939.6 and 972.5 dollars.

This is the pvalue of Z when X = 972.5 subtracted by the pvalue of Z when X = 939.6. So

X = 972.5

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{972.5 - 965}{14.97}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

X = 939.6

Z = \frac{X - \mu}{s}

Z = \frac{939.6 - 965}{14.97}

Z = -1.7

Z = -1.7 has a pvalue of 0.0446

0.6915 - 0.0446 = 0.6469

So

P(939.6 < X < 972.5) = 0.6469

3 0
2 years ago
What is the value of the expression below when z =5 and w=5? 9z-3w
zysi [14]
This is just about substitution!! 9(5)-3(5), 3 • 5 = 15
9 • 5 = 45
so Now you have, 45 - 15 = 30
7 0
3 years ago
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Klio2033 [76]

Answer:

12

Step-by-step explanation:

If 12 apples makes 2 cups, we can assume that 6 apples make 1 cup.

Take the number of apples and divide it by 6 in order to find out the number of cups that can be made.

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3 years ago
Which type of graph would be best for showing the average yearly bonus amounts for employees in different departments of an IT c
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I believe it is C. a histogram
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