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3 years ago

Which is greater 2/3 or 1/3

2 answers:

3 0

Because they are both 3 on the bottom so you should see if 2 is bigger than 1 or not, and the answer is yes!
so 2/3 is greater than 1/3 :)))
I hope this is helpful
have a nice day

olya-2409 [2.1K]3 years ago

3 0

Lets say you have a pizza which is cut into 3 pieces. Now if you get 2 slices and your friend gets 1 slice. Since you got more it means that you got bigger portion than you friend.

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There are twenty classes at each of two middle schools. The number of students in each class at each school is shown in the dot

tatuchka [14]

Answer:

There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

Step-by-step explanation:

The rest of the question is the attached figure.

It is required to compare between the mean number of students for the data in the plots.

The mean is sum of all data divided by the number of data.

The data set of Poplar Middle School:

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

So, The mean = 435/20 = 21.75

The data set of Oak Middle School:

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

So, The mean = 483/20 = 24.15

The difference in mean = 24.15 - 21.75 = 2.4

So, the correct statement is:

There are about 2 more students in each class at Oak Middle School than at Poplar Middle School.

7 0

3 years ago

Read 2 more answers

5x^2 - 6x - 28 = 0 please help me do this

Yanka [14]

Answer:

x= 3 5 + 1 5 √149 or x= 3 5 + −1 5 √149

4 0

3 years ago

Can someone help me plz.

masha68 [24]

He’s right, but can I have Brainly I’m so close to virtuoso

5 0

3 years ago

— 25 — 3х + 5 or – 3х +5 — 31

zysi [14]

Answer:

both should

be equal to hope my work is correct or helps

Step-by-step explanation:

first one

-25<-3x+5 subtract 5 from both sides

-25-5=-30

5-5=0

then divide by -3

-30 divided by -3 =10

x=10

so it is equal to not less than

second one

-3x+5<-31

subtract 5 from both sides 5-5=0

-31 -5=-36

then divide both sides by -3

x=12

6 0

3 years ago

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

To find when will the ball land, we set h=0

$2x^2-12x+20=0$