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k0ka [10]
3 years ago
10

OKKKKK I NEED A NEW PHONE !!! ( online school sucks)

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0

<em>Yea online school does suck, but when u need help, they wont give u the help u need. And also u get called on to do something when u dont want to. Have a nice day!! :)</em>

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Whats the answer to log <img src="https://tex.z-dn.net/?f=log_%7Bx%2B2%7D%20%289x%29%20%3D2" id="TexFormula1" title="log_{x+2} (
lyudmila [28]

Answer:

x= 1, 4

Step-by-step explanation:

log_{x+2} (9x) =2\\\\9x = (x+2)^2 \\\\(x+2)^2 - 9x = 0\\\\x^2 +4x + 4-9x = 0\\\\x^2 - 5x +4= 0\\\\x^2 - 4x-x+4=0\\\\x(x-4)-1(x-4)=0\\\\(x-4)(x-1)=0\\\\x-4 =0\: or\: x - 1=0\\\\x = 4\: or\: x = 1\\\\x = 1,\: 4

4 0
3 years ago
What is the expected value of the above spinner?
vova2212 [387]

A spinner, is divided in half, vertically. The right side, is labeled For the spinner below, calculate the expected value. Answer: 1 4 ( − 3 ) + 1 4 ( 10 ) ...
4 0
3 years ago
3x + x- 2x + 8 = 3x + x
Arada [10]

Answer:

x=4

Step-by-step explanation:

3x+x - 2x + 8= 3x + x

4x- 2x +8 = 4x

2x + 8= 4x

8= 2x

x=4

5 0
3 years ago
A graph of a quadratic function y = f(x) is shown below.
spin [16.1K]

We are given a graph of a quadratic function y = f(x) .

We need to find the solution set of the given graph of a quadratic function .

<em>Note: Solution of a function the values of x-coordinates, where graph cut the x-axis.</em>

For the shown graph, we can see that parabola in the graph doesn't cut the x-axis at any point.

It cuts only y-axis.

Because solution of a graph is only the values of x-coordinates, where graph cut the x-axis. Therefore, there would not by any solution of the quadratic function y = f(x).

<h3>So, the correct option is 2nd option :∅.</h3>
8 0
4 years ago
Read 2 more answers
If 1-cosA = 1/2 , Then find the value of sinA.
zimovet [89]

Step-by-step explanation:

Given :

1- cosA = 1/2

or, CosA = 1 -1/2

Therefore ; CosA = 1/2 = b/h

According to the Pythagoras theorem,

P = root under h^2 - b^2

= root under (2)^2 - (1)^2

= root under 4 -1

= root 3

Again,

SinA = P/h

= root 3 / 2

8 0
2 years ago
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