Answer:
750 < p < 1500
Step-by-step explanation:
The total cost of the affair for p attendees is ...
750 +2.25p
The average cost is that number divided by p. The answer choices suggest that "between" means that the cost per person cannot be 2.75 or 3.25. Applying the limits to the average cost, we get ...
2.75 < (750 +2.25p)/p < 3.25
2.75 < 750/p + 2.25 < 3.25 . . . . . . . . separating the fraction parts
0.50 < 750/p < 1.00 . . . . . . . . . . . . . . subtract 2.25
2 > p/750 > 1 . . . . . . . . . . . . . . . . . . . . . take the reciprocal*
1500 > p > 750 . . . . . . . . matches choice 4
_____
* Taking the reciprocals of numbers with the same sign reverses their order:
2 < 3 but 1/2 > 1/3
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An alternate approach to the solution would be to multiply by p:
0.50p < 750 < 1.00p
To solve this requires it be made into two inequalities:
0.50p < 750 ⇒ p < 1500
and
750 < 1.00p ⇒ 750 < p
Then these would need to be recombined to form the answer:
750 < p < 1500
<u>Answer:</u>
<u>Step-by-step explanation:</u>
First set the equation to 0
Second, get the 12 on the right side of the equal sign by adding a -12 to each side
Square root both sides of the equal sign.
Take the square root on left sides of the equal sign.
Take the square root on the right side of the equal sign. Remember 
<u>AND</u>
.1.Scale Factor of Triangle STU to Triangle PQR= 1.5
2.Scale Factor of Trapezoid EFGH to Trapezoid JKLM =2
3. about 90 armadillo
1.Side ST: 15 ÷ Side PQ: 10 = 1.5
2.Side JM: 14 ÷Side EH: 7 = 2
3.843/7=120.428571429
843/4=210.75
210.75-120.428571429=90.321428571
This rounds to 90 armadillo
Hope this helps :3 ❤
The increasing order of the horizontal widths of their asymptote rectangles is dependent on the values gotten from y = ± x.
<h3>What is a Hyperbola?</h3>
This is defined as a two-branched open curve formed by the intersection of a plane perpendicular to the bases of a double cone.
The rectangular hyperbola has two asymptotes which are defined as y = ± x in this scenario.
Read more about Hyperbola here brainly.com/question/3351710
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Answer:
The answer is No.
Step-by-step explanation:
The answer is no because an integer is any whole number that isn't a fraction. So this can be positive and still be an integer.
