To create hydrogen and oxygen from water, you would need to perform which type of reaction?
1 answer:
You might be interested in
Answer:
Rate constant k = 1.57*10⁻⁵ s⁻¹
Explanation:
Given reaction:
Expt [A] M [B] M Rate [M/s]
1 3.40 4.16 1.82*10^-4
2 4.59 4.16 3.32*10^-4
3. 3.40 5.46 1.82*10^-4
where k = rate constant
x and y are the orders wrt to A and B
To find x:
Divide rate of expt 2 by expt 1
To find y:
Divide rate of expt 3 by expt 1
Therefore: x = 2, y = 0
To find k
Use rate for expt 1:
ΔH = -15.78 KJ when 25.0 g of S₈ reacts.
<h3>What is Balanced Chemical Equation ?</h3>The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given reaction balanced equation is:
1/8 S₈(s) + H₂(g) → H₂S(g) ΔH = -20.22kj
Now,
When 1 mol will react, then ΔH = -20.2 × 8
= -161.6 KJ
When 1 mol of S8 = 8 × 32 g
= 256 g
When 256g of S8 react ΔH = -161.6 KJ
When 1 g reacts, ΔH =
=- 0.63125 KJ
When 25 g reacts, ΔH = - 0.63125 × 25
= -15.78 KJ
Thus from the above conclusion we can say that ΔH = -15.78 KJ when 25.0 g of S₈ reacts.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
#SPJ4