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MArishka [77]
3 years ago
12

You wish to prepare 100 mL of 0.600 M HCl from concentrated HCl (12.85 M). You are provided with a 100 mL volumetric flask and a

10 mL graduated pipet with 0.00 line at the top and calibration lines each 0.1 mL. When filled to the 0.00 mL line this pipet would dispense 10.00 mL of solution when drained leaving only the final inside drop. At what volume reading on the pipet should you start dispensing the 12.85 M HCl to have the correct number of moles to give the 0.600 M solution when dispensed into the volumetric flask?
Chemistry
1 answer:
Soloha48 [4]3 years ago
8 0

Answer:

Because we need to dispense 4.7 mL, the volume reading in the pipet is the 5.3 mL line.

Explanation:

First we use C₁V₁=C₂V₂ in order to <u>calculate the required volume of concentrated HCl</u> (V₁):

12.85 M * V₁ = 0.600 M * 100 mL

V₁ = 4.7 mL

<u>So we need to dispense 4.7 mL of the concentrated HCl solution</u>. The mark in the pipet that would contain that volume would be 10.0 - 4.7 = 5.3 mL

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La luna es materia? ayuda pisos es para yaaaaaaa!! ;)​
Valentin [98]

Answer:

La Luna ? Deberia ser materia

Explanation:

6 0
3 years ago
1.How many mL of 0.401 M HI are needed to dissolve 5.97 g of BaCO3?
garri49 [273]

Answer:

The answer to your question is:

1.- volume = 0.151 l or 151 ml

2.- 0.241 l  or 241 ml of NaOH

Explanation:

1.-

Data

V = ? HI = 0.401 M

BaCO3 = 5.97 g

                     2HI(aq)    +    BaCO3(s)   ⇒   BaI2(aq) + H2O(l) + CO2(g)

MW BaCO3 = 137 + 12 + 48 = 197 g

                     197 g of BaCO3 ----------------- 1 mol

                     5.97 g                -----------------   x

                     x = (5.97 x 1) /197

                    x = 0.03 mol of BaCO3

                    2 moles of HI ----------------  1 mol of BaCO3

                    x                     ----------------  0.03 mol of BaCO3

                    x = (0.03 x 2) / 1

                   x = 0.060 mol of HI

Molarity = moles / volume

volume = moles / molarity

volume = 0.060 / 0.401

volume = 0.151 l or 151 ml

2.-

V = ?    NaoH 0.757 M

Co⁺² Volume = 167 ml   0.548 M

             CoSO4(aq) + 2NaOH(aq)   ⇒   Co(OH)2(s) + Na2SO4(aq)

Moles of Co = Molarity x  volume

Moles of Co = 0.548 x 0.167

Moles of Co = 0.092

                                 1 mol of CoSO4 -------------- 2 moles of NaOH

                                0.092 moles      ---------------   x

                                x = (0.092 x 2) /1

                               x = 0.183 moles of NaOH

Volume of NaOH = moles / molarity

                             = 0.183 / 0.757

                            = 0.241 l  or 241 ml of NaOH

6 0
3 years ago
If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) --&gt;
irakobra [83]

The products will be ZnCl_2(s) + H_2(g)

<h3>Chemical reactions</h3>

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

More on chemical reactivity can be found here: brainly.com/question/9621716

#SPJ1

3 0
2 years ago
How do the independent and dependent variables in an experiment compare?
DENIUS [597]
An independent variable<span> is the </span>variable<span> that is changed or controlled in a scientific </span>experiment<span> to test the effects on the </span>dependent variable<span>. </span>
4 0
3 years ago
Match these items
masha68 [24]
The correct matches are as follows:

<span>1.instantaneous combustion 
</span>G.burning<span>

2.mass of substances before and after a reaction is the same
</span>C.Law of Conservation of Matter<span>

3.substances that combine
</span>A.reactants
<span>
4. Yields or makes
</span>B.arrow symbol 
<span>
5.rapid oxidation
</span>F.explosion<span>

6.new substance
</span>D.product
<span>
7.slow oxidation
</span>E.rust
<span>
Hope this answers the question. Have a nice day.

</span>
4 0
3 years ago
Read 2 more answers
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