Answer:
The amount invested at 9% is $93000
The amount invested at 10% is $303000
Step-by-step explanation:
Let the amount invested at 9% interest rate be x
And the amount invested at 10% rate be y
Simple Interest from x in a year = 0.09x
Simple Interest from y in a year = 0.1y
But y = 24000 + 3x
And the sun of the interests, 0.09x + 0.1y = 38670
Now we have a simultaneous eqn
y = 24000 + 3x (eqn 1)
0.09x + 0.1y = 38670 (eqn)
Substitute y into eqn 2
0.09x + 0.1(24000 + 3x) = 38670
0.09x + 2400 + 0.3x = 38670
0.39x = 38670 - 2400
x = 36270/0.39 = $93000
y = 24000 + 3x = 24000 + 3 × 93000 = $303000
In order to figure out whether Luis or Isabella skates farther to get to school, we have to create a common denominator between the two fractions that represent the distance that each person walks.
The least common denominator of 3 and 4 is 12. This means that we have to change both fractions into equal fractions with denominators of 12.
To figure this out, we must set up a proportion.
2/3 = x/12
To solve this proportion, we must cross-multiply the fractions. We get:
24 = 3x
If we divide both sides by the coefficient of x which is 3, to get the variable x alone, we get:
x = 8
Therefore, 2/3 = 8/12, so Luis skates 8/12 mile from his home to school.
If we do the same process for the 2/4 mile to get to school for Isabella, we get 6/12, because both fractions are equal to 1/2.
Therefore, we know that Luis skates 8/12 mile to school and Isabella skates 6/12 mile to get to school. Because they have the same denominator, we can just compare the numerators. We know that 8 is greater than 6, thus Luis skates farther to get to school.
Answer:
128
Step-by-step explanation:
5+2=7
5-2=3
2^5=32
2^2=4
32*4=128
Hope this helps:)
P(7,6), Q(1,6), R(4,2)
We have PQ parallel to the x axis. We'll call that the base,
b = 7 - 1 = 6
The altitude is then the y difference h = 6 - 2 = 4
The area is 
Answer: 12 square units
In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:
(7,6), (1,6), (4,2)
(1,6), (4,2), (7,6)
The area is then half the absolute value of the sum of the cross products:
