6x^2 - 8 = 4x^2 + 7x
6x^2 - 4x^2 - 7x - 8 = 0
2x^2 - 7x - 8 = 0
discriminant = b^2 - 4ac; where a = 2, b = -7 and c = -8
d = (-7)^2 - 4(2)(-8)
d = 49 + 64
d = 113
the discriminant is greater than zero, so there are two real roots
To convert a quadratic<span> from y = ax</span>2<span> + bx + c form to </span>vertex<span> form, y = a(x - h)</span>2+ k, you use the process of completing the square. Let's see an example. Convert y = 2x2<span>- 4x + 5 into </span>vertex<span> form, and state the </span>vertex<span>.</span>
<h3>Given Equation:-</h3>

<h3>Step by step expansion:</h3>


























