Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:

Where
is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is
. The critical points of the function are those who make
:


The critical value inside the interval is
.

The second step is to find the values of the function at the endpoints of the interval:

The biggest value of f is gived by
, therefore
is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Answer:
A)-1
Step-by-step explanation:
3x-5≥4x-3
3x-4x≥-3+5
-x≥2
x≤-2
(-infinity,-2]
-1 x
-2,-3,-5 ✓
The geometric sequence is 3, 9, 27, 81, 243, 729 because each time it is multiplied by 3.
Answer:
The length of the hypotenuse is 4.1 in
Step-by-step explanation:
By definition, the sine of an angle is:

In this case they tell us that the opposite side measures 4 inches and the angle x measures 80 °.
With this information we can find the length of the hypotenuse h

Finally the length of the hypotenuse is 4.1 in
2x^2 + 3x + 8 = 0
Answer: B) -3 + I √55 over 4.