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3 years ago

1. The difference between the product of nine and a number and three times the number.

Mathematics

1 answer:

Alik [6]3 years ago

7 0

Answer:

Question 1:

• Let the number be x

${ \tt{9x - 3x}} \\ { \boxed{ \tt{ = 6x}}}$

Question 2:

${ \tt{5x - 4x}} \\ { \boxed { \tt{ = x}}}$

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Evaluate −3w − 6p for w=2 and p = −7

kap26 [50]

-3w-6p when w=2 and p=-7

-3(2)-6(-7)

= -6 + 42

= 36

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3 years ago

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What is the answer for these questions?

PIT_PIT [208]

Answer:

a.) yes

b.) no

c.) yes

d.) yes

Step-by-step explanation:

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3 years ago

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anu borrows 12,500 as 12% per annum for 3 years at simple interest find the simple interest she has to pay at the end of 3 years

marishachu [46]

Answer:

The interest is 4,500

Step-by-step explanation:

We use the simple interest formula,

I = Prt

where

I = interest

P = principal amount = 12,500

r = interest rate = 12% = 0.12

t = time = 3 years

I = Prt

I = 12,500 × 0.12 × 3

I = 4,500

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2 years ago

Renee is sewing a quilt whose pattern contains right triangles.

Mashutka [201]

Answer:

8 inches

Step-by-step explanation:

The area of a triangle is ...

A = 1/2bh

Filling in the given values, we have ...

24 = 1/2b(6)

24/3 = b = 8 . . . . . divide by the coefficient of b

The base of each triangular quilt piece is 8 inches long.

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3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

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3 years ago

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