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LenKa [72]
3 years ago
6

In previous years, Cox Transport reacquired 4 million treasury shares at $22 per share and, later, 2 million treasury shares at

$25 per share. If Cox now sells 2 million treasury shares at $27 per share and determines cost as the weighted-average cost of treasury shares, by what amount will Cox’s paid-in capital - share repurchase increase? (Enter your answer in millions (i.e., 10,000,000 should be entered as 10).)
Business
1 answer:
crimeas [40]3 years ago
3 0

Answer:

$8 million

Explanation:

Weighted-average cost = [(4,000,000 × $22) + (2,000,000 × $25)] ÷ (4,000,000 + 2,000,000) = $23

Increase in paid-in capital - share repurchase per share = selling price —Weighted-average cost = $27 - $23 = $4

Amount of increase in paid-in capital—share repurchase = Number of treasury shares × $4 = 2 million × $4 = $8 million

Therefore, Cox’s paid-in capital - share repurchase will increase by $8 million.

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Answer: B. Yes. Branding allows the mushrooms to be easily identified in the future. ​ Thus, if they were of inferior​ quality, the company would lose customers and go out of business over time.

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Which item(s) are tax deductible for consumers who are buying or renting a home?
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I think it'd D: Mortgage interest and property taxes. 
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Badger Enterprises purchased aluminum from JG Metals. When Badger Enterprises recorded this transaction, they made entries into
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Perpetual inventory system - is the type of inventory system Badger Enterprise uses. A perpetual inventory system is when companies keep track of each individual purchase and sale of inventory continuously. If they use a periodic inventory system, they will do it periodically, or over a given point in time. 
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What is the difference between a sole proprietorship and an LLC?
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7 0
3 years ago
Let S represent the amount of steel produced (in tons). Steel production is related to the amount of labor used (L) and the amou
Phantasy [73]

Solution

S = 15 x L^{0.2} x C^{0.8}

Total cost, T = wL + rC = 50L + 100C

Total revenue, R = Output price (P) x Quantity = P x 15 x L^{0.2}x C^{0.8}

(a)

Optimization problem will be:

Max R = P x 15 x L^{0.2} x C^{0.8}

Subject to T = 50L + 100C

(b) When S = 50,000

Cost is minimized when (MPL / MPC) = w / r

MPL = \partialR / \partialL = P x 15 x 0.2 x (C / L)^{0.8} = P x 3 x (C / L)^{0.8}

MPC = \partialR / \partialC = P x 15 x 0.8 x (L / C)^{0.2} = P x 12 x (L / C)^{0.2}

MPL / MPC = (3/12) x (C / L) = 50/100

C / 4L = 1/2

4L = 2C

2L = C

Substituting in production function,

15 x L^{0.2} x C^{0.8} = S

15 xL^{0.2} x (2L)^{0.8} = 50,000

15 x 2^{0.8} x L^{0.2} x L^{0.8} = 50,000

L = 50,000 / (15 x 20.8)

L = 1,914.50

C = 2L = 3,829.00

Total cost ($) = 50 x 1,914.50 + 100 x 3,829.00 = 95,725.00 + 382,900 = 478,625.00

Note: This optimization problem can be solved without using Solver too, as shown here.

6 0
3 years ago
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