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aliya0001 [1]
3 years ago
6

How to solve this math problem 50.2 ÷ 10? ​

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

5.04

Step-by-step explanation:

If you divide 50 by 10, taking away the 0.2, you get 5. 0.2÷5=0.04

So you would get 5.04

Bond [772]3 years ago
7 0

When you divide a decimal by (a multiple of) 10, you want to move the decimal to the left once for every zero in the number.

<em>For example:</em>

If you were to divide it by 100, then you move the decimal twice.

So when you divide by 10, you move the decimal once, and the answer is 5.02.

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What is the length of
saveliy_v [14]

Answer:

17 units

Step-by-step explanation:

Because the triangle is isosceles, 2 of its sides are congruent; namely, the two sides that are opposite of the 2 congruent angles are contruent.

Because of the reason stated above, we can see that AC is congruent to BC, meaning that:

x+9=2x-8

-x      -x

9=x-8

+8  +8

17  = x

Notice that BC is equal to x, so 17 is our final answer.

6 0
2 years ago
Need help in less than 5 minutes brainliest to the first/most helpful answer!! Need it speedy!!!!
Sonbull [250]

Answer:

1.) True

2.) False

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6 0
2 years ago
A: 5x − 2y = 10
Nuetrik [128]

Answer:

D) Multiply A by -4 and B by 5

Step-by-step explanation:

5x-2y=10

4x+3y=7

----------------

-4(5x-2y)=-4(10)

5(4x+3y)=5(7)

----------------------

-20x+8y=-40

20x+15y=35

---------------------

23y=-5

y=-5/23

5x-2(-5/23)=10

5x+10/23=10

5x=10-10/23

5x=230/23-10/23

5x=220/23

x=(220/23)/5

x=(220/23)(1/5)

x=220/115

x=44/23

7 0
3 years ago
Find the Peronist of the figure below, composed of an isoceles trapezoid and one semicircle, round to the nearest tenth place
Mamont248 [21]

Given:

Diameter of circle is 10

Find : Perimeter

Sol:.

Perimeter of semi circle

\begin{gathered} =\pi r \\ =\pi(\frac{10}{2}) \\ =5\pi \\ =15.707 \end{gathered}

Perimeter of shape is:

\begin{gathered} =14+12+12+15.707 \\ =53.707 \end{gathered}

7 0
1 year ago
What’s the sum of the measures of the exterior angles of a 53-gon?
Ronch [10]

Option B

The sum of the measures of the exterior angles of a 53 - gon is 360 degrees

<em><u>Solution:</u></em>

The formula for sum of exterior angles "n" is:

N = 180n-180(n-2)

Distribute 180

N = 180n - 180n + 360\\\\N = 360

Therefore, sum of measure of exterior angles is 360 degrees

<h3>Sum of the measures of all the exterior angles of any polygon, irrespective of its number of sides is always 360 degrees</h3>

Thus, in a 53 gon, sum of measure of exterior angles is 360 degrees

7 0
3 years ago
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