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aliya0001 [1]
3 years ago
6

How to solve this math problem 50.2 ÷ 10? ​

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

5.04

Step-by-step explanation:

If you divide 50 by 10, taking away the 0.2, you get 5. 0.2÷5=0.04

So you would get 5.04

Bond [772]3 years ago
7 0

When you divide a decimal by (a multiple of) 10, you want to move the decimal to the left once for every zero in the number.

<em>For example:</em>

If you were to divide it by 100, then you move the decimal twice.

So when you divide by 10, you move the decimal once, and the answer is 5.02.

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Factorise completely<br> 12y² + 4y
otez555 [7]

Step-by-step explanation:

12y^{2}  + 4y \\4y( \frac{12y^{2} }{4y}  +  \frac{4y}{4y} ) \\ 4y(3y + 1)

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Which choice is NOT a way to find 7 ÷ 3?<br> A- 1/3 of 7<br> B- 7 × 1/3<br> C- 1/7 of 3<br> D- 7/3
lutik1710 [3]
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Because all others are correct and this one is incorrect.
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Eye Color Hair Color Blue Gray Green Brown Marginal Total Blond 42 5 21 10 78 Red 12 22 19 12 65 Brown 22 5 12 34 73 Black 9 3 1
iogann1982 [59]
The <u>correct answer</u> is:

18.

Explanation:

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In AGHI, the measure of ZI=90°, the measure of ZG=5°, and IG = 57 feet. Find the
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3 0
3 years ago
An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y
Kay [80]

Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=31+31-2=60  

Replacing the info given we got:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0
3 years ago
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